Answer:
x = 7°
<GDH = 112°
<FDH = 192°
<FDE = 135°
Step-by-step explanation:
If DE bisects <GDH this means that <GDE = <EDH
Given <GDE = (8x+1)° and <EDH = (6x+15)° then;
8x+1 = 6x+15
8x-6x = 15-1
2x = 14
x = 7°
Since <GDH = <GDE + <EDH
<GDH = 8x-1+6x+15
<GDH = 14x+14
<GDH = 14(7)+14
<GDH = 98+14
<GDH = 112°
For <FDH,
Note that sum of angle on a straight line is 180°
<FDH = <FDG + <GDE + <EDH
<FDH = <FDG + <GDH
<FDG = 180-(43+8x+1)
<FDG = 180-44-8x = 136-8x
<FDH = 136-8x+112
<FDH = 248-8x
<FDH = 248-8(7)
<FDH = 248-56
<FDH = 192°
For <FDE;
<FDE = <FDG + <GDE
<FDE = 136-8x+8x-1
<FDE = 135°
2x^2 • x^2 = 2x^4
First, multiply the terms with the same base by adding their exponents
2x^2+2
Then, add the numbers
2x^4
Answer:
6 
Step-by-step explanation:
Use the triangle area equation

plug in the base (4ft) times the height (3ft) then divide by two
Answer:
rate of motorboat: b
rate of current: c
So the rate the boat travels upstream is $b - c$, and the rate it travels downstream is $b + c$
Step-by-step explanation:
d = rt
200 = (b - c)\cdot 5
200 = (b + c)\cdot 4
b - c = 40
b + c = 50
Adding these equations, we get:
2b = 90
b = 45
So
c = 50 - 45 = 5
<u>Therefore the rate of the boat is 45kph, and the rate of the current is 5kph</u>
Hope this helps :)
Answer:
12
Step-by-step explanation: