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3 years ago

8

Find the area of the shape?

1 answer:

Dominik [7]3 years ago

7 0

Answer:

12π ≈ 37.7

Step-by-step explanation:

A = π*r² - π*r²/4

A = 3πr²/4

r = 4

A = 3π(4)²/4

A = 12π ≈ 37.7

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What should you conclude if, after solving an equation, the result is 1/2= 2/3

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no solution

Step-by-step explanation:

1/2 = 2/3

This is not a true statement. If you get this after solving an equation, there is no solution to your equation.

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3 years ago

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Step-by-step explanation:

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If a line is 10 feet long but needs to be reduced to 80% of its original, how long will the new line be?

motikmotik

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Step-by-step explanation:

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3 years ago

Find the solution of the given initial value problem in explicit form. y′=(1−5x)y2, y(0)=−12 Enclose numerators and denominators

Nata [24]

Answer:

The solution is $y=-\frac{12}{12x-30x^2+1}$ .

Step-by-step explanation:

A first order differential equation $y'=f(x,y)$ is called a separable equation if the function $f(x,y)$ can be factored into the product of two functions of $x$ and $y$ :

$f(x,y)=p(x)h(y)$

where $p(x)$ and $h(y)$ are continuous functions.

We have the following differential equation

$y'=(1-5x)y^2, \quad y(0)=-12$

In the given case $p(x)=1-5x$ and $h(y)=y^2$ .

We divide the equation by $h(y)$ and move $dx$ to the right side:

$\frac{1}{y^2}dy\:=(1-5x)dx$

Next, integrate both sides:

$\int \frac{1}{y^2}dy\:=\int(1-5x)dx\\\\-\frac{1}{y}=x-\frac{5x^2}{2}+C$

Now, we solve for $y$

$-\frac{1}{y}=x-\frac{5x^2}{2}+C\\-\frac{1}{y}\cdot \:2y=x\cdot \:2y-\frac{5x^2}{2}\cdot \:2y+C\cdot \:2y\\-2=2yx-5yx^2+2Cy\\y\left(2x-5x^2+2C\right)=-2\\\\y=-\frac{2}{2x-5x^2+2C}$

We use the initial condition $y(0)=-12$ to find the value of C.

$-12=-\frac{2}{2\left(0\right)-5\left(0\right)^2+2C}\\-12=-\frac{1}{c}\\c=\frac{1}{12}$

Therefore,

$y=-\frac{2}{2x-5x^2+2(\frac{1}{12})}\\y=-\frac{12}{12x-30x^2+1}$

4 0

3 years ago

The equation of a circle is (X+12)^2+(y+16)^2=r^2, and the circle passes through the origin. The equation of the circle then cha

serious [3.7K]

Answer:

$x=\sqrt{r_{2} +y-16(r2-y+16)+30}$ R2

$r=\sqrt{x^2+24x+y2+32y+400}$

Step-by-step explanation:

3 0

3 years ago