Question

The equation of a circle is (X+12)^2+(y+16)^2=r^2, and the circle passes through the origin. The equation of the circle then changes to ( x-30)^2+(y-16)^2=(r2)^2 and the circle still passes through the origin. What are the values of r1 and r2? Answers: r1 = 10 and r2 = 17 r1 = 10 and r2 = 34 r1 = 20 and r2 = 17 r1 = 20 and r2 = 34

Answer 1

Answer:

$x=\sqrt{r_{2} +y-16(r2-y+16)+30}$R2

$r=\sqrt{x^2+24x+y2+32y+400}$

Step-by-step explanation: