Answer:
Juan = 93 years.
Gabe = 31 years.
Catherine = 25 years.
Step-by-step explanation:
Let the age of Juan = J
Let the age of Gabe = G
Let the age of Catherine = C
<em>Translating the word problem into an algebraic equation, we have;</em>
..........equation 1
........equation 2
........equation 3
<em>We would solve the linear equations by using the substitution method; </em>
<em>Substituting equation 2 into equation 1;</em>
........equation 4
<em>Substituting equation 2 and equation 4 into equation 3;</em>
<em>Simplifying the equation, we have;</em>
C = 25 years.
To find G; from equation 2
Substituting the value of "C" into equation 2, we have;
G = 31 years.
To find J; from equation 1
Substituting the value of "G" into equation 1, we have;
J = 93 years.
<em>Therefore, Juan is 93 years old, Gabe is 31 years old and Catherine is 25 years old. </em>
3/5=x/25
Multiply both sides by 25 to get: x = 25(3/5)x = 15
Hope I wasn't too late!
Answer:
Step-by-step explanation:
First you need to write it down. Now, 1st step of the math, how many times will 7 go into 4? 0 times. So you have to do how many times 7 goes to 44. It goes in 6 times bc 7 times 7 is 49. Now, subtract 42 form 44 which is 2. Bring down the 2, you get 22. 7 goes into 22 3 times, subtract 21 from 22. One. So your answer is 63 remainder one!
Two significant Figures I believe because you want to go with the least amount of sig figs that are already in your problem which would be 2 in 7500 because the zeros are not significant
Answer:start fraction 1 over 16 end fraction.
Step-by-step explanation: