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Nikitich [7]
4 years ago
9

Rewrite as a simplified fraction3.83 =​

Mathematics
2 answers:
alukav5142 [94]4 years ago
7 0

Answer:

3 83/100

Step-by-step explanation:

The part 83/100 can not be simplified more because 83/100 is in its simplest form already.

sveticcg [70]4 years ago
3 0

Answer:

3 83/100

Step-by-step explanation:

Hello Applebannana11!

Let's take a slower more simple approach first.

Since the places for decimals are ten(ths) and hundred(ths), we can see that it is going to be \frac{83}{100}.

Since, 3 is our whole digit, it will be the first thing.

3 \frac{83}{100}.

Now, we check if \frac{83}{100} can be simplified.

We see the GCF of 83 and 100 is 1.

Therefore, \frac{83}{100} cannot be simplified.

Since we don't need to simplify 3, our final answer is $\boxed{3 \frac{83}{100} }.

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Edin has £300 in his saving account. His bank offers him a fixed 5% intrest per annum ,for three years.How much interest will he
lakkis [162]

Answer:

£45

Step-by-step explanation:

Given data

P= £300

R=5%

T= 3 years

SI= PRT/100

substitute

SI= 300*5*3/100

SI=4500/100

SI= £45

Hence the interest is  £45

8 0
3 years ago
1. The structure of the supports for the hill consists of steel beams that
Darina [25.2K]

a) Parallel for both line segments have the same slope = -5/4

b)  55º

Step-by-step explanation:

a) To verify the parallelism of these line segments, It's necessary to find the slope of each one. Parallel lines share the same slope value:

m_{BC}=\frac{0-150}{120-0}=-\frac{-5}{4}\\m_{AD}=\frac{0-125}{100-0}=-\frac{5}{4}

b) If ∠DAB = 125°, what is the measure of ∠CBA? Justify your reasoning.

Those beams do not form a parallelogram because:

Using the formula of distance between those points

d=\sqrt{(y_{2}-y_1)^{2}-(x_{2}-x_{1})^2  

\overline {AB}=25\: \: \: \overline{CD}=20\: \: \overline{AD}=160 \: \: \overline{BC}=192

So this is a trapezoid.  And two adjacent angles within a trapezoid are supplementary, so If ∠DAB = 125º then 180 - ∠CBA=55º

3 0
3 years ago
5. What is the area of a trapezoid with the following measurements? Base 1=15
zaharov [31]

Answer:

129.5 cm²

Step-by-step explanation:

The area (A) of a trapezoid is calculated as

A = \frac{1}{2} h(a + b)

where h is the height and a, b the parallel bases

Here h = 7, a = 15 and b = 22 , thus

A = \frac{1}{2} × 7 × (15 + 22)

   = 0.5 × 7 × 37

   = 129.5

3 0
4 years ago
Please help me write an equation for this polynomial graphed
oksian1 [2.3K]

The equation for this polynomial graphed will be P(x) = a(x + 2)(x + 1)(x – 3)³.

<h3>What is polynomial?</h3>

A polynomial expression is an algebraic expression with variables and coefficients.

The graph of the polynomial is given below.

From the graph, the roots of the polynomial will be -2, -1, and 3.

Then the factor of the polynomial will be

(x + 2), (x + 1), and (x – 3)

Then the polynomial will be

P(x) = a(x + 2)(x + 1)(x – 3)³

More about the polynomial link is given below.

brainly.com/question/17822016

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3 0
2 years ago
Read 2 more answers
Rickey has been commissioned to paint a mural that is allowed to have an area of 50 square meters. To make the rectangle shape o
Leno4ka [110]

Answer:

12.808 meter is the length should Rickey use for the mural.

Step-by-step explanation:

Area of the mural = A = 50 m^2

Length of the mural = l

Width of the mural = w

l = 5 + 2w

Area of the rectangle = l × w

A=(5+2w)\times w

50 m^2=5w+2w^2

2w^2+5w-50=0

Solving above equation with the help of Completing squares method:

(\sqrt{2}w)^2+2\times \sqrt{2}w\times \frac{5}{2\sqrt{2}}+(\frac{5}{2\sqrt{2}})^2-50=(\frac{5}{2\sqrt{2}})^2

(a+b)^2=a^2+b^2+2ab

(\sqrt{2}w+\frac{5}{2\sqrt{2}})^2=(\frac{5}{2\sqrt{2}})^2+50

(\sqrt{2}w+\frac{5}{2\sqrt{2}})^2=\frac{25}{8}+50

(\sqrt{2}w+\frac{5}{2\sqrt{2}})^2=\frac{425}{8}

(\sqrt{2}w+\frac{5}{2\sqrt{2}})=\pm\sqrt{\frac{425}{8}}

w = 3.904 m (accept)

w = -6.404 m (reject)

l = (5 + 2w)m = 5 + 2 × (3.904) m= 12.808 m

12.808 meter is the length should Rickey use for the mural.

3 0
3 years ago
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