Ask question

Ask question

All categories

zhannawk [14.2K]

3 years ago

9

Michelle purchased a kids table with a square top if the area of the square top is 400 square inches what is the length of one o

f the sides

2 answers:

worty [1.4K]3 years ago

7 0

400 in² = (20 in)²

The area of a square is the square of the side length.

The length of one of the sides is 20 inches.

Ray Of Light [21]3 years ago

5 0

Answer: 20 inches

Step-by-step explanation:

We know that the area of a square is given by :-

$\text{Area}=(\text{Side})^2$

Given : Michelle purchased a kids table with a square top if the area of the square top is 400 square inches .

Let s be the side of the square , then we have the following equation:-

$s^2=400$

Taking square root on both the sides , we get

$s=\sqrt{400}=\sqrt{20\times20}=20$

Hence, the length of one of the sides = 20 inches

You might be interested in

PLEASE SOLVE!!<br> IN A HURRY <br> WILL name the BRAINLIEST!!!

ICE Princess25 [194]

Answer:

62

Step-by-step explanation:

96 divided by 2 = 48

48 - 14 = 34

48 + 14 = 62

34 + 62 = 96 (total cars washed)

You're welcome

8 0

3 years ago

7 1/2 divided by 3/4

vagabundo [1.1K]

Answer:

7 1/2 divided by 3/4= 10

5 0

3 years ago

Please help thank you

zlopas [31]

Answer:

A is the real part and B is the imaginary part. i is an imaginary figure. b is how many imaginary figures there are, making it represent an imaginary part

3 0

3 years ago

The Great Pyramid in Giza, Egypt, is a square pyramid. The dimensions of the pyramid at the time of its completion are shown in

ryzh [129]

Answer:

Area of square pyramid is $153883.8\ m^{2}$ .

Step-by-step explanation:

Diagram of the given scenario is shown below,

Given that,

The Great Pyramid in Giza, Egypt is a square pyramid. The area of base shape is made up with square is $154 \ m^{2}$ . The side of the square is $230 \ m$ and The height of each triangle is $187 \ m$ .

So, Area of Square shape = $154 \ m^{2}$

Side of square = $230 \ m$

Height of each triangle = $187 \ m$

Finding the Height of triangular shape which is here known as slant height.

In Δ ABO, applying Right angle pythagorean Theorem,

Base $(BO)$ = $\frac{230}{2} = 115\ m$

Height $(AO)$ = $187\ m$

Now,

∴ $AB^{2} = AO^{2} \ + \ BO^{2}$

⇒ $AB= \sqrt{AO^{2} \ + \ BO^{2} }$

⇒ $AB= \sqrt{187^{2} \ + \ 115^{2} }$

⇒ $AB= \sqrt{34969 \ + \ 13225 }$

⇒ $AB= 219.53 \ m$

Then,

Area of square pyramid = $area \ of \ square + \ 4\times area \ of \ traiangle$

= $side\times side + 4\times\frac{1}{2}\times AB\times Base$

= $230\times 230 \ + 2\times 219.53\times 230$

= $52900 + 100983.8$

= $153883.8 \ m^{2}$

Hence, Area of square pyramid is $153883.8\ m^{2}$ .

6 0

3 years ago

PLEASE HELP ILL GIVE BRAINLIEST!

Svetradugi [14.3K]

For qn2 :
2(n+7) = 2n + 14
hence, the answer is C as 2n + 2(7) = 2n + 14 as well

3 0

3 years ago

Read 2 more answers