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cestrela7 [59]
3 years ago
5

Determining Key Aspects of a Quadratic Function

Mathematics
1 answer:
Blizzard [7]3 years ago
5 0

Answer:

Step-by-step explanation:

The vertex can be located most easily by completing the square of

f(x) = -X^2 - 2x - 1 (which is equivalent to -(x^2 + 2x + 1).  The latter expression can be rewritten as -(x + 1)^2, which indicates that the x-coordinate of the vertex is -1.  The corresponding y-value is 0.  Vertex is at (-1, 0).

The function is increasing for x < -1 and decreasing for x > -1.

The domain of the function is "all real numbers."

The range is (-infinity, 0)

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Please help me figure this out.
xz_007 [3.2K]

Answer:

Quotient: x+7

Remainder: -2

Step-by-step explanation:

Divide the terms (x² ÷ x =x)↓

(x² + 11x + 26) ÷ (x + 4) =x

Subtract x² + 4x (You have to the sign if each term)

(x² + 11x + 26) ÷ (x + 4) =x

-x² - 4x

-------------------

      7x + 26      

Divide the terms (7x ÷ x = 7)

x² + 11x + 26) ÷ (x + 4) =x + 7

Multiply the quotient by the dividend (x + 4) × 7 = 7x+28

(x² + 11x + 26) ÷ (x + 4) =x

-x² - 4x

-------------------

      7x + 26      

      7x + 28

------------------

           = -2 Remainder

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3 years ago
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In order to solve the following system of equations by subtraction, which of
PSYCHO15rus [73]

Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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