The answer to the question
<span><span> Let ABC be an isosceles triangle with AB = AC. Let M denote the midpoint of BC (i.e., M is the point on BC for which MB = MC). Thena)<span> </span>Triangle ABM is congruent to triangle ACM.b)<span> </span>Angle ABC = Angle ACB (base angles are equal)c)<span> </span>Angle AMB = Angle AMC = right angle.d)<span> </span>Angle BAM = angle CAM
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Answer:
840mm^3
Step-by-step explanation:
V=(1/2)LWH
L=14
W=10
H=12
14*12*10=1680
Then divide by 2
840
Wow ! That's some cosine !
No angle has a cosine greater than ' 1 '.
The question has no answer.