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Tasya [4]
2 years ago
11

Tyra's family is spending the afternoon in Millersville. They plan to see a movie and then explore

Mathematics
1 answer:
Xelga [282]2 years ago
3 0

Answer: 36+4h=60

36+4h-36=60-36

4h=24

4h÷4=24÷4

h=6

So, after the move they can spend 6 hours there. (6×4=24, 24+36=60, they will spend $60 if they spend 6 hours there, $56 if they spend 5 hours there and don't want to spend $60).

Step-by-step explanation:

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Guys pls help me! ASAP!
Makovka662 [10]

Answer:

Step-by-step explanation:

2. area of a triangle is 1/2 b h

1/2 (5 * 2) = 5 yd squared

area of the circle is pi r squared

you only need 1/2 of this area

find all these areas and add them together.

6. this is just a square sitting on a rectangle.

36 x 36 for the square

36 x 60 for the rectangle

add these together.

8. this a 1/2 circle and a triangle.

area of a circle is pi r squared

r is 7 in this problem

the area of a triangle is 1/2 b h

height is 7x2 here or 14

add the two together.

4 0
3 years ago
What is 5/12 times 6 in multiply fractions with whole numbers
KiRa [710]
5/12*6  =5/12*6/1 crosscancle you get 5/2 the you get 2 1/2
3 0
3 years ago
1. (a) Solve the differential equation (x + 1)Dy/dx= xy, = given that y = 2 when x = 0. (b) Find the area between the two curves
erastova [34]

(a) The differential equation is separable, so we separate the variables and integrate:

(x+1)\dfrac{dy}{dx} = xy \implies \dfrac{dy}y = \dfrac x{x+1} \, dx = \left(1-\dfrac1{x+1}\right) \, dx

\displaystyle \frac{dy}y = \int \left(1-\frac1{x+1}\right) \, dx

\ln|y| = x - \ln|x+1| + C

When x = 0, we have y = 2, so we solve for the constant C :

\ln|2| = 0 - \ln|0 + 1| + C \implies C = \ln(2)

Then the particular solution to the DE is

\ln|y| = x - \ln|x+1| + \ln(2)

We can go on to solve explicitly for y in terms of x :

e^{\ln|y|} = e^{x - \ln|x+1| + \ln(2)} \implies \boxed{y = \dfrac{2e^x}{x+1}}

(b) The curves y = x² and y = 2x - x² intersect for

x^2 = 2x - x^2 \implies 2x^2 - 2x = 2x (x - 1) = 0 \implies x = 0 \text{ or } x = 1

and the bounded region is the set

\left\{(x,y) ~:~ 0 \le x \le 1 \text{ and } x^2 \le y \le 2x - x^2\right\}

The area of this region is

\displaystyle \int_0^1 ((2x-x^2)-x^2) \, dx = 2 \int_0^1 (x-x^2) \, dx = 2 \left(\frac{x^2}2 - \frac{x^3}3\right)\bigg|_0^1 = 2\left(\frac12 - \frac13\right) = \boxed{\frac13}

7 0
2 years ago
Factorise <br> 84xy+196x-36y-84
LenaWriter [7]

Hi,

84xy+196x-36y-84

4(21xy+49x-9y-21)

4(7x × (3y+7)-9y-21)

4(7x × (3y+7)-3(3y+7)

4(3y+7)×(7x-3)

4 0
3 years ago
What is the factored form of 5x2 − 18x − 8? (5x + 4)(x + 2) (5x + 2)(x − 4) (5x + 1)(x + 8) (5x + 1)(x − 8)
olya-2409 [2.1K]
Hello! So, this question is in the form of ax² - bx - c. First thingd first, let's multiply a and c together. c = -8 and a = 5. -8 * 5 is -40. Now, let's find two factors that have a product of 40, but a sum of 18. If you list the factors, you see that 2 and 20 have a product of 40, but  2 - 20 is -18. The factors we will use are -2 and 20.

How to factor it:

For this question, you can use something called a box method and factor it by finding a factor of each column and row. Just make 4 boxes and put 5x² on the top left and -40 on the bottom left box. Put 2x on the top right box and -20x on the bottom left box. Now, factor out for each row and column. The factors should be 5x + 2 for the top part and x - 4 for the side. It should look like (5x + 2)(x - 4). Let's check it. Solve it by using the FOIL method and you get 5x² - 20x + 2x - 8. Combine like terms and you get 5x² - 18x - 8. There. The answer is B: (5x + 2)(x - 4)

Note: The box method may be challenging at first, but it can be really helpful on problems like these.
6 0
3 years ago
Read 2 more answers
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