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4 years ago

Solve for each equation h divided by 4/9 for h = 5 1/3 A) 2 10/27 B) 10 C) 12

1 answer:

6 0

Solve for each equation
h divided by 4/9 for h = 5 1/3

h 16/3
------- = -----------------
4/9 4/9
= 16/3 * 9/4
= 12
answer is C) 12

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Answer:

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How many times greater than √2 is√32? Can anybody help out here?

Anarel [89]

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Step-by-step explanation:

Root32= 4×root2

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Write functions for each of the following transformations using function notation. Choose a different letter to represent each f

kupik [55]

Answer:

$(a)\ T_{a,b} =(x +a,y+b)$

$(b)\ F_{y\ axis} = (-x,y)$

$(c)\ F_{x\ axis} = (x,-y)$

$(d)\ R_{o,90^o} = (-y,x)$

$(e)\ R_{o,180^o} = (-x,-y)$

$(f)\ R_{o,270^o} = (y,-x)$

Step-by-step explanation:

Solving (a): Translate a units right, b units up

When a function is translated a units right, the number of units will be added to the x coordinate

When a function is translated b units up, the number of units will be added to the y coordinate.

So, we have:

$T_{a,b} =(x +a,y+b)$

Solving (b): Reflect across y-axis

When a function is translated across the y-axis, the x coordinate gets negated.

So, we have:

$F_{y\ axis} = (-x,y)$

Solving (c): Reflect across x-axis

When a function is translated across the x-axis, the y coordinate gets negated.

So, we have:

$F_{x\ axis} = (x,-y)$

Solving (d): 90 degrees rotation counterclockwise

When a function is rotated 90 degrees counterclockwise, the y-coordinates gets negated and then swapped with the x-coordinate.

So, we have:

$R_{o,90^o} = (-y,x)$

Solving (e): 180 degrees rotation counterclockwise

When a function is rotated 180 degrees counterclockwise, the coordinates are negated.

So, we have:

$R_{o,180^o} = (-x,-y)$

Solving (f): 270 degrees rotation counterclockwise

When a function is rotated 270 degrees counterclockwise, the x-coordinates gets negated and then swapped with the y-coordinate.

So, we have:

$R_{o,270^o} = (y,-x)$

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3 years ago

Can someone please help me with that ? So confused

nasty-shy [4]

That's what it will look like

7 0

3 years ago

Can you solve this? I need help. I don't understand.

ZanzabumX [31]

Answer:

2 sqrt(5) OR 4.5

Step-by-step explanation:

You have to know Pythagorean theorem to solve this question.

a^2 + b^2 = c^2

To use this theorem you have to have a right triangle. There are two right triangles in your image. The lower (larger) one has two sides labeled, so you can use Pythagorean thm to find the third side. There's a short cut, bc some right triangles have easy-to-memorize lengths of the sides. 3-4-5 is one of these number sets. A multiple of this is 6-8-10. We could've solved:

b^2 + 8^2 = 10^2

But it would've come out the same. The unlabeled side is 6.

We can use the 6 and the 4 on the smaller right triangle and use the Pythagorean thm again to solve for x.

4^2 + x^2 = 6^2

16 + x^2 = 36 subtract 16 from both sides.

x^2 = 20

Take the square root of both sides.

sqrt (x^2) = sqrt 20

x = 2 sqrt(5) which is approximately 4.472.

2 sqrt(5) is an exact answer if that is what they are asking for. 4.472 is an approximation to the nearest thousandth. It would be 4.47 to the nearest hundredth or 4.5 to the nearest tenth.

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2 years ago