Join the centre O to the chord (let it be MN) & let OH be the perpendicular to the chord
OH bisects MN into 2 equal parts (each one is x/2) OMH is a right triangle with one side =8, the second leg =x/2 & the hypotenuse = 12 (Radius) Apply Pythagoras:
If th<span>e equation y=1/3x is the boundary line for the inequality y>1/3 x, then the solution set is illustrated by shading the area ABOVE the line y=(1/3)x.</span>
