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Genrish500 [490]
3 years ago
10

Write a model for the statement V varies jointly as h and the fifth power of r. Group of answer choices LaTeX: V=khr^5 V = k h r

5 LaTeX: V=\frac{1}{khr^5} V = 1 k h r 5 LaTeX: V=5khr V = 5 k h r LaTeX: V=kh+kr^5 V = k h + k r 5 LaTeX: V=\frac{kh}{r^5}
Mathematics
1 answer:
hjlf3 years ago
7 0

Answer:

Option A)

V = khr^5

Step-by-step explanation:

We are given the following in the question:

V varies jointly as h and the fifth power of r.

V\propto h\\V\propto r^5

Combing the two equations, we get,

V\propto hr^5

Now, removing the sign of proportionality and adding the constant of proportionality, we get,

V = khr^5

where k is the constant of proportionality.

Thus, the correct answer is

Option A)

V = khr^5

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Question 14 of 25What is the complete factorization of the polynomial below?x³+x² + 4x+4O A. (x-1)(x+2)(x+2)B. (x + 1)(x + 2)(x
mote1985 [20]

GIVEN:

We are given the following polynomial;

x^3+x^2+4x+4

Required;

We are required to factorize this polynomial completely.

Step-by-step explanation;

To factorize this polynomial, we start by grouping;

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We now take the common factor in each group;

\begin{gathered} x^2(x+1)+4(x+1) \\  \\ (x^2+4)(x+1) \end{gathered}

Next, we factorize the first parenthesis. To do this we set the equation equal to zero and solve for x as follows;

\begin{gathered} x^2+4=0 \\  \\ Subtract\text{ }4\text{ }from\text{ }both\text{ }sides: \\  \\ x^2=-4 \\  \\ Take\text{ }the\text{ }square\text{ }root\text{ }of\text{ }both\text{ }sides: \\  \\ x=\pm\sqrt{-4} \\  \\ x=(\pm\sqrt{-1}\times\sqrt{4}) \\  \\ x=\pm2i \end{gathered}

Therefore, the factors of the other parenthesis are;

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Therefore, the complete factorization of the polynomial is;

ANSWER:

(x+1)(x+2i)(x-2i)

Option C is the correct answer.

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Answer:

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Now that you know the total sum, subtract all other angles to find x:

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