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3 years ago

I’m really lost........... 6^5 x 5^-7

Mathematics

1 answer:

Naddik [55]3 years ago

5 0

Answer:

0.0995328 OR 7776 /78125

It's okay to be a little lost. When I have exponents and all this "fun" stuff, I use Desmos graphing calculator. It will help you GREATLY. Let me know if you wan the link...

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A horseback rider travels 2 miles in 12 minutes. At this speed, how long does it take to travel 5 miles?

CaHeK987 [17]

Divide the time he traveled by the distance to find how fast he travels 1 mile, then multiply that by 5 miles:

12 minutes / 2 miles = 6 minutes per mile.

6 minutes per mile x 5 miles = 30 total minutes.

7 0

4 years ago

What is the length of side x?

Feliz [49]

Answer:

7 cm

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

A food manufacturer uses an extruder (a machine that makes bite size cookies)that yields revenue for the firm at a rate of $200

julsineya [31]

Answer:

$1300

Step-by-step explanation:

The extruder yields a revenue of $200per hour

Y denotes the number of breakdown per day.

The daily revenue generated is given as

R = 1600 - 50Y^2

We have an average of 2 breakdown per day

Lamda = 2

Represent lamda as β

E(Y) = β

E(Y(Y-1)) = β^2

E(Y^2) = E[Y(Y-1)] + E(Y)

= β^2 + β

E(R) = E(1600 - 50Y^2)

= 1600 - 50E(Y^2)

= 1600 - 50(β^2 +β)

Recall that β = lamda = 2

= 1600 - 50(2^2 + 2)

= 1600 - 50(4+2)

= 1600 - 50(6)

= 1600 - 300

= 1300

$1300

The expected daily revenue of the extruder is $1300

3 0

3 years ago

A 10-foot ladder is leaning against a vertical wall. If the bottom of the ladder is being pulled away from the wall at the rate

Alex777 [14]

Answer:

The area is changing at 15.75 square feet per second.

Step-by-step explanation:

The triangle between the wall, the ground, and the ladder has the following dimensions:

H: is the length of the ladder (hypotenuse) = 10 ft

B: is the distance between the wall and the ladder (base) = 6 ft

L: the length of the wall (height of the triangle) =?

dB/dt = is the variation of the base of the triangle = 9 ft/s

First, we need to find the other side of the triangle:

$H^{2} = B^{2} + L^{2}$

$L = \sqrt{H^{2} - B^{2}} = \sqrt{(10)^{2} - B^{2}} = \sqrt{100 - B^{2}}$

Now, the area (A) of the triangle is:

$A = \frac{BL}{2}$

Hence, the rate of change of the area is given by:

$\frac{dA}{dt} = \frac{1}{2}[L*\frac{dB}{dt} + B\frac{dL}{dt}]$

$\frac{dA}{dt} = \frac{1}{2}[\sqrt{100 - B^{2}}*\frac{dB}{dt} + B\frac{d(\sqrt{100 - B^{2}})}{dt}]$

$\frac{dA}{dt} = \frac{1}{2}[\sqrt{100 - B^{2}}*\frac{dB}{dt} - \frac{B^{2}}{(\sqrt{100 - B^{2}})}*\frac{dB}{dt}]$

$\frac{dA}{dt} = \frac{1}{2}[\sqrt{100 - 6^{2}}*9 - \frac{6^{2}}{\sqrt{100 - 6^{2}}}*9]$

$\frac{dA}{dt} = 15.75 ft^{2}/s$

Therefore, the area is changing at 15.75 square feet per second.

I hope it helps you!

5 0

3 years ago

Which points did you include in your response? Check all that apply

iogann1982 [59]

Answer:

any of them work

Step-by-step explanation:

8 0

3 years ago