Answer:
7
Step-by-step explanation:
.
1] Given that the value of x has been modeled by f(x)=12500(0.87)^x, then:
the rate of change between years 1 and 5 will be:
rate of change is given by:
[f(b)-f(a)]/(b-a)
thus:
f(1)=12500(0.87)^1=10875
f(5)=12500(0.87)^5=6230.3
rate of change will be:
(6230.3-10875)/(5-1)
=-1161.2
rate of change in years 11 to 15 will be:
f(11)=12500(0.87)^11=2701.6
f(15)=12500(0.87)^15=1,547.74
thus the rate of change will be:
(1547.74-2701.6)/(15-11)
=-288
dividing the two rates of change we get:
-288/-1161.2
-=1/4
comparing the two rate of change we conclude that:
The average rate of change between years 11 and 15 is about 1/4 the rate between years 1 and 5.
The answer is D]
2] Given that the population of beavers decreases exponentially at the rate of 7.5% per year, the monthly rate will be:
monthly rate=(n/12)
where n is the number of months
=7.5/12
=0.625
This is approximately equal to 0.65%. The correct answer is A. 0.65%
If Paul mows the lawn once, he earns 1*25.50. If he mows it twice, he earns 2*25.50, and so on. So, he earns L*25.50. But, he spends 3.50. So the equation is:
Answer: 29 miles per gallon.
Reasoning: 856 miles/29.4 gallons = 29.1156462585 (rounded to the nearest mile = 29)
Hope this helped!
Answer:
1/ -2.65
2/ 1/8
3/ 14.28
4/ -7.9
Step-by-step explanation:
Just add and subtract.
