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DIA [1.3K]
4 years ago
10

What is the danger zone for bacteria? A. Below 40 B. Between 40 and 140 C. Above 140 D. The only safe temperatures are between 4

0
Mathematics
2 answers:
timurjin [86]4 years ago
4 0

Answer:

B

Explanation:

Bacteria grow most rapidly in the range of temperatures between 40 °F and 140 °F, doubling in number in as little as 20 minutes. This range of temperatures is often called the "Danger Zone." Never leave food out of refrigeration over 2 hours.

Delicious77 [7]4 years ago
4 0

Answer:

B. Between 40 and 140 Fahrenheit

Step-by-step explanation:

This is called the "Danger Zone" because between these temperatures bacteria grow the fastest. Doubling time can be as little as 20 minutes.

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30 points!!<br><br> Please help!!!!<br><br> 7+3^2(-5+1)divided by 2
Zielflug [23.3K]

Answer:

7+3^2(-5+1) divided by 2 is -11

6 0
3 years ago
Read 2 more answers
I need help solving #9 &amp; #11! It's geometry but I'm just really stuck<br><br>​
Vikentia [17]

Answer:

9)x=11 y=3

11)x=18 y=5

Step-by-step explanation:

9) 9x+25=13x+19                   13x-19+17y+5=180

   9x+44=13x                         129+17y=180

   44=4x                                 17y=51

   11=x                                     y=3

11) 49+3x=7x-23                    3x=11y-1

7 0
3 years ago
Question:
MArishka [77]

Answer:

73°

Step-by-step explanation:

Given, Angle A = 17° and Angle B = 90°

As it is a triangle, sum of all the angles are 180°

so,

⇒ Angle A + Angle B + Angle C = 180°

⇒ 17° + 90° + Angle C = 180°

⇒ Angle C = 73°

5 0
3 years ago
What is the volume of a regular hexagonal prism with a side length of 4 and a height of 9? Please give the answer as square root
likoan [24]
The height of an equilateral triangle with side s is s*sqrt(3)/2
The area of an equilateral triangle is therefore s^2*sqrt(3)/4
The area of a hexagon with side s is 6 times the area of an equilateral triangle
=6*s^2*sqrt(3)/4
=3s^2*sqrt(3)/2
 
Here s=4, 
Area of base (hexagon) = 3*4^2*sqrt(3)/2=24sqrt(3)
Volume of prism
=(base area)*height
=24sqrt(3)*9
=216sqrt(3)

6 0
3 years ago
The domain f(x)=1/2x-3 (-3,-2,-1,0,3,4) what is the range
mihalych1998 [28]

Answer:

-2

Step-by-step explanation:

because we can solve and get answer

4 0
3 years ago
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