Answer:
105 cc of 7% solution
245 cc of 17% solution
Step-by-step explanation:
If x = volume of 7% solution, and y = volume of 17% solution, then:
x + y = 350
0.07x + 0.17y = 0.14(350)
Solve with substitution:
0.07x + 0.17(350 − x) = 0.14(350)
0.07x + 59.5 − 0.17x = 49
10.5 = 0.10x
x = 105
y = 245
If a 15 lbs dog eats................................17/8 cups of food
a 34 lbs dog will eat,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,? cups
(34 * 17/8)/15=(34*17)/(15*8)=289/15= 19 4/15 cups of food
20*6=120seconds +3600second in an hour so 3600*4=14400
1210+14400=14520
14520 is the answer I hope this helps!
Answer:

Step-by-step explanation:
Consider the options for this question are as follow,
Here, In triangles ABC and PQR,
AB = c, BC = a, AC = b, PQ = r, QR = p and PR = q,
Since,

We know that,
The corresponding sides of similar triangles are in same proportion,
Thus,




3.) An extreme value refers to a point on the graph that is possibly a maximum or minimum. At these points, the instantaneous rate of change (slope) of the graph is 0 because the line tangent to the point is horizontal. We can find the rate of change by taking the derivative of the function.
y' = 2ax + b
Now that we where the derivative, we can set it equal to 0.
2ax + b = 0
We also know that at the extreme value, x = -1/2. We can plug that in as well.

The 2 and one-half cancel each other out.


Now we know that a and b are the same number, and that ax^2 + bx + 10 = 0 at x = -1/2. So let's plug -1/2 in for x in the original function, and solve for a/b.
a(-0.5)^2 + a(-0.5) + 10 = 0
0.25a - 0.5a + 10 = 0
-0.25a = -10
a = 40
b = 40
To determine if the extrema is a minima or maxima, we need to go back to the derivative and plug in a/b.
80x + 40
Our critical number is x = -1/2. We need to plug a number that is less than -1/2 and a number that is greater than -1/2 into the derivative.
LESS THAN:
80(-1) + 40 = -40
GREATER THAN:
80(0) + 40 = 40
The rate of change of the graph changes from negative to positive at x = -1/2, therefore the extreme value is a minimum.
4.) If the quadratic function is symmetrical about x = 3, that means that the minimum or maximum must be at x = 3.
y' = 2ax + 1
2a(3) + 1 = 0
6a = -1
a = -1/6
So now plug the a value and x=3 into the original function to find the extreme value.
(-1/6)(3)^2 + 3 + 3 = 4.5
The extreme value is 4.5