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3 years ago

5

2 answers:

7 0

24 because the ratio is 5:8 and you have to multiply 5 by 3 to get 15
so you have to do the same thing to 8 and multiply it by 3 to get 24

natta225 [31]3 years ago

5 0

5 drops of red paint for 8 drops of yellow paint therefore
5*3=15 drops of red paint
8*3= 24 drops of yellow paint

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the table shows the types of popcorn buckets sold at a concession station for one day. what percent of the buttered popcorn buck

vlada-n [284]

Hi there! The answer is about 23%

First we need to find the total amount of buttered popcorn sold. This is 182 + 140 + 97 = 419 buckets.

To find the percentage of the buttered popcorn buckets that were large, we use the following formula:
$\frac{part}{total} \times 100\%$

Filling in this formula brings us to our answer:
$\frac{97}{419} \times 100\% = 23.15$
Hence, the answer is about 23%

7 0

3 years ago

You have a die with two red faces, two blue faces, and two white faces. What is the probability the die is tossed and shows eith

elena-s [515]

Answer:

1/3??? im probably wrong but i would answer it like this.

Step-by-step explanation:

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2 years ago

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If all guitar players are musicians, then all musicians are guitar players.

IrinaVladis [17]

Answer:

This does not make sense.

Step-by-step explanation:

Just because you are a musician does not mean you play the guitar.

You can play the piano and a trumpet, but not be able to play a guitar!

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3 years ago

Read 2 more answers

At Western University the historical mean of scholarship examination scores for freshman applications is 900. A historical popul

vampirchik [111]

Answer:

a) Null Hypothesis: $\mu =900$

Alternative hypothesis: $\mu \neq 900$

b) The 95% confidence interval would be given by (910.05;959.95)

c) Since we confidence interval not ocntains the value of 900 we fail to reject the null hypothesis that the true mean is 900.

d) $z=\frac{935 -900}{\frac{180}{\sqrt{200}}}=2.750$

Since is a bilateral test the p value is given by:

$p_v =2*P(Z>2.750)=0.0059$

Step-by-step explanation:

a. State the hypotheses.

On this case we want to check the following system of hypothesis:

Null Hypothesis: $\mu =900$

Alternative hypothesis: $\mu \neq 900$

b. What is the 95% confidence interval estimate of the population mean examination score if a sample of 200 applications provided a sample mean x¯¯¯= 935?

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X=935$ represent the sample mean for the sample

$\mu$ population mean (variable of interest)

$\sigma=180$ represent the population standard deviation

n=200 represent the sample size

The confidence interval for the mean is given by the following formula:

$\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (1)

In order to calculate the mean and the sample deviation we can use the following formulas:

$\bar X= \sum_{i=1}^n \frac{x_i}{n}$ (2)

$s=\sqrt{\frac{\sum_{i=1}^n (x_i-\bar X)}{n-1}}$ (3)

The mean calculated for this case is $\bar X=3278.222$

The sample deviation calculated $s=97.054$

Since the Confidence is 0.95 or 95%, the value of $\alpha=0.05$ and $\alpha/2 =0.025$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.025,0,1)".And we see that $z_{\alpha/2}=1.96$