All categories

3 years ago

Solve the equation for y. 9x+y=10

Mathematics

2 answers:

skad [1K]3 years ago

7 0

You said 9x + y = 10

Subtract 9x
from each side: y = -9x + 10

Nostrana [21]3 years ago

3 0

Y=-9x+10 is the equation solved for y.

You might be interested in

How many pounds of bananas cost $3.75?

Kryger [21]

Answer:

$5 pounds of bananas cost $3.75.$

8 0

2 years ago

Read 2 more answers

Your family drives from Austin Texas to Tampa Florida. The trip is 1145 mi and lasts four days. How many miles should your famil

Colt1911 [192]

286.2...round down soo...286 miles

5 0

3 years ago

Find the greatest common factor: 24y^8 + 6y^6

Marrrta [24]

Find the Greatest Common Factor (GCF)

Factor out the GCF. (Write the GCF first. Then, in parenthesis divide each term by the GCF.)

6y^6(24y^8/6y^6 + 6y^6/6y^6)

Simplify each term in parenthesis

7 0

3 years ago

Hellppppppp with this twoooooooo

liberstina [14]

15.

0.20*x = 0.01*x + 38 => 0.19*x = 38 =>( 19/100 )*x = 38 => x = 3800/19 => x = 200.

6 0

3 years ago

Please Help!!

Genrish500 [490]

Given

$a\sqrt{x+b}+c=d$

we have

$\sqrt{x+b}=\dfrac{d-c}{a}$

Squaring both sides, we have

$x+b=\dfrac{(d-c)^2}{a^2}$

And finally

$x=\dfrac{(d-c)^2}{a^2}-b$

Note that, when we square both sides, we have to assume that

$\dfrac{d-c}{a}>0$

because we're assuming that this fraction equals a square root, which is positive.

So, if that fraction is positive you'll actually have roots: choose

$a=1,\ b=0,\ c=2,\ d=6$

and you'll have

$\sqrt{x}+2=6 \iff \sqrt{x}=4 \iff x=16$

Which is a valid solution. If, instead, the fraction is negative, you'll have extraneous roots: choose

$a=1,\ b=0,\ c=10,\ d=4$

and you'll have

$\sqrt{x}+10=4 \iff \sqrt{x}=-6$

Squaring both sides (and here's the mistake!!) you'd have

$x=36$

which is not a solution for the equation, if we plug it in we have

$\sqrt{x}+10=4 \implies \sqrt{36}+10=4 \implies 6+10=4$

Which is clearly false

7 0

3 years ago