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LuckyWell [14K]
3 years ago
13

What is the value of the positive zero of the function , f, defined by f(x) =x^2-121

Mathematics
2 answers:
slavikrds [6]3 years ago
8 0

Answer:

The positive zero is 11

Step-by-step explanation:

Given in the question an equation,

f(x) =x² - 121

We are asked to find the positive zero of f(x)

means x > 0 for which f(x) = 0

so,

<h3>  x² - 121 = 0</h3>

 x² = 121

Take square root on both sides of the equation

√x² = √121

  x =  ±11

which means that x = 11 and x = -11

Since x > 0 so we will reject x =-11 and we will accept x = 11

 

Diano4ka-milaya [45]3 years ago
3 0

Answer: 11

Step-by-step explanation:

You need to substitute f(x)=0 into the function given:

f(x) =x^2-121\\0 =x^2-121

Now you need to solve for the variable "x", to do this, first you must add 121 to both sides of the function:

(121)+0=x^2-121+(121)\\121=x^2

Now apply square root to both sides of the function. Then, you get:

\±\sqrt{121}=\±\sqrt{x^2}\\\\\±\sqrt{121}=x\\\\x_1=11\\x_1=-11

The value of the positive zero of the function is 11.

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