The slope, m, of a linear equation can be found using the formula m = v2 - v1/x2 - x1 , where the x- and the y-values come from two ordered pairs, and (x1,y1) and (x2,y2). What is an equivalent equation solved for y2?
A. y2 = mx2 - x1 + y1
B. y2 = mx2 - x1 - y1
C. y2 = m(x2 - x1) + y1
D. y2 = m(x2 - x1) - y1
HELP PLEASE!!!!!
1 answer:
Answer:
y2 = m(x2-x1)+y1
Step-by-step explanation:
Given the expression;
m = y2-y1/x2-x1
Making y2 the subject of the formula
Cross multiply
m(x2-x1) = y2-y1
Add y1 to both sides
m(x2-x1)+y1 = y2-y1+y1
m(x2-x1)+y1 = y2
Hence y2 = m(x2-x1)+y1
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