D=event that chip selected is defective
d=event that chip selected is NOT defective
Four possible scenarios for the first two selections:
P(DDD)=15/100*14/99*13/98=13/4620
P(DdD)=15/100*85/99*14/98=17/924
P(dDD)=85/100*15/99*14/99=17/924
P(ddD)=85/100*84/99*15/98=17/154
Probability of third selection being defective is the sum of all cases,
P(XXD)=P(DDD)+P(DdD)+P(dDD)+P(ddD)
=3/20
You write like that that's how I do it
Answer:
Multiply both sides by 2
Subtract l from both sides
Divide each side by 3
(2R -l)/3 =w
Step-by-step explanation:
R = (l+3w)/2
Multiply both sides by 2
2R = 2* (l+3w)
2R = l+3w
Subtract l from both sides
2R - l = l-l +3w
2R -l = 3w
Divide each side by 3
(2R-l) /3 = 3w/3
(2R -l)/3 =w
i think its true
i have to add 20 characters or more so here you go
Answer:
30 degrees
Step-by-step explanation:
To figure out theta is using a bit of simple trigonometry.
2sin(theta) = 1
= sin(theta) = 0.5
Using arcsin (sin^-1) we can isolate x
x = arcsin(0.5)
x = 30
