I’m not so sure i’m sorry
Answer:
How many drinks should be sold to get a maximal profit? 468
Sales of the first one = 345 cups
Sales of the second one = 123 cups
Step-by-step explanation:
maximize 1.2F + 0.7S
where:
F = first type of drink
S = second type of drink
constraints:
sugar ⇒ 3F + 10S ≤ 3000
juice ⇒ 9F + 4S ≤ 3600
coffee ⇒ 4F + 5S ≤ 2000
using solver the maximum profit is $500.10
and the optimal solution is 345F + 123S
Answer:
(8,10) is not a solution
Step-by-step explanation:
Cuz it’s not on both inequality shaded part but just one of them and also when we substitute one is true and the other one is false
2x + y _< 8
2(8) + 10 _< 8
18 + 10 _< 8
28 _< 8 false
X + y _> 4
8 + 10 -> 4
18 _> 4 true
Answer:
The answer is R(2).
Step-by-step explanation:
hope this helped!