Answer:

Step-by-step explanation:
Please refer to the attached figure for the labeling and construction in the given figure:
Given that minor angle of arc AB is
.
Or in other words, we can say that angle subtended on the center O by the arc is
.
Now, PA and PB are the tangents so, if we join the center of circle O with A and B, the angles formed are right angles.
i.e.

Now, we know that sum of internal angles of a quadrilateral is equal to
.
Here, we have the quadrilateral AOPB.

Hence, the correct answer is:
