Question

Use the sum and difference rule to find the derivative of y=(3x^5)+(2x^4)-(2x)

Answer 1

Answer:

$y^{'} = 15x^{4} +8x^{3} -2.$

Step-by-step explanation:

$y=3x^{5} +2x^{4} -2x;\\y^{'} = ({3x^{5}^}) {'} +({2x^{4}}) {'} - ({2x}) {'}; \\y^{'} = 3*5x^{5-1} +2*4x^{4-1} -2*1x^{1-1} ;\\\\ y^{'} = 15x^{4} +8x^{3} -2.$