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Vika [28.1K]
4 years ago
14

At Sam’s Swimming Pool Cleaning, Sam charges each of his 85 customers $25 per week for 52 weeks of service every year. Since poo

l cleaning is a service, it has no cost other than labor and supplies, which cost Sam $48,000 each year. Calculate Sam’s annual net income. a. $2,125 b. $4,420 c. $62,500 d. $110,500
Mathematics
1 answer:
AlekseyPX4 years ago
5 0

Answer:

the answer is $62,500

Step-by-step explanation:

1. you first multiply $25 by 85 people

2. you multiply the answer by 52 weeks

3. then subtract 48,000 sa the labor

1. $25×85=2,125

2. ans×52=110,500

3. ans-48,000=62,500

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If you add or subtract two rational numbers, is the result sometimes, always, or never rational?
lawyer [7]

Answer:

Always

Step-by-step explanation:

8 - 9 = -1

1/3 - 1/6 = 1/6   are 2 examples

8 0
3 years ago
A store brought a case of disposable cameras for $300. The store's profit p on the cameras is a function of the number c of came
rewona [7]

Answer:

Range: {-300, -210, 0, 72}

Step-by-step explanation:

Given:

Cost price of each camera = $300

The function for profit 'p' is given as:

p=6c-300

Where, 'p' is the profit and 'c' is the number of cameras sold.

The domain of the function is: {0, 15, 50, 62}

Now, range is the output of the above function for the given domain.

Here, 'c' is the independent variable and hence the domain.

So, plugging in the values of 'c' in the above function will give the set of values of range.

For c=0, the profit is given as:

p(0)=6(0)-300\\p(0)=-300

For c=15, the profit is given as:

p(15)=6(15)-300\\p(15)=90-300=-210

For c=50, the profit is given as:

p(50)=6(50)-300\\p(50)=300-300=0

For c=62, the profit is given as:

p(62)=6(62)-300\\p(62)=372-300=72

Therefore, the range of the given function is: {-300, -210, 0, 72}

The above range represents the profit of the store when 'c' number of cameras are sold. The domain represents the number of cameras that are sold by the store.

So, negative profit means the store has a loss on selling that number cameras.

The store suffers loss upto 50 cameras sold. When the number of cameras sold is 50, there is neither loss not profit. At this point, total cost price equals total selling price. This is also break even point.

After this point, the store will have a net profit. So, for 62 cameras sold, the net profit of the store is $72.

6 0
3 years ago
In a survey it was found that 260 people like summer, 100 like spring, 75 liked both seasons, and 15 liked neither season. How m
Lelu [443]
450 people were surveyed
6 0
3 years ago
A university dean is interested in determining the proportion of students who receive some sort of financial aid. Rather than ex
Olenka [21]

Answer:

a

 The  90% confidence interval that  estimate the true proportion of students who receive financial aid is

     0.533  <  p <  0.64

b

   n = 1789

Step-by-step explanation:

Considering question a

From the question we are told that

      The sample size is  n = 200

      The number of student that receives financial aid is k = 118

Generally the sample proportion is  

      \^ p = \frac{k}{n}

=>   \^ p = \frac{118}{200}

=>   \^ p = 0.59

From the question we are told the confidence level is  90% , hence the level of significance is    

      \alpha = (100 - 90 ) \%

=>   \alpha = 0.10

Generally from the normal distribution table the critical value  of \frac{\alpha }{2}  is  

   Z_{\frac{\alpha }{2} } =  1.645

Generally the margin of error is mathematically represented as  

     E =  Z_{\frac{\alpha }{2} } * \sqrt{\frac{\^ p (1- \^ p)}{n} }

 =>E =  1.645 * \sqrt{\frac{0.59 (1- 0.59)}{200} }

=>  E = 0.057

Generally 90% confidence interval is mathematically represented as  

      \^ p -E <  p <  \^ p +E

  =>  0.533  <  p <  0.64  

Considering question b

From the question we are told that

    The margin of error  is  E = 0.03

From the question we are told the confidence level is  99% , hence the level of significance is    

      \alpha = (100 - 99 ) \%

=>   \alpha = 0.01

Generally from the normal distribution table the critical value  of   is  

   Z_{\frac{\alpha }{2} } = 2.58

Generally the sample size is mathematically represented as      

        [\frac{Z_{\frac{\alpha }{2} }}{E} ]^2 * \^ p (1 - \^ p )

=>      n = [\frac{2.58}{0.03} ]^2 * 0.59 (1 - 0.59 )

=>      n = 1789

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4 years ago
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