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Pani-rosa [81]
3 years ago
12

the side length of the state flag of Colorado are in the ratio of 2:3 if the flag is 12 ft long what is the height?​

Mathematics
1 answer:
yanalaym [24]3 years ago
6 0

Answer:

The height is 8

Step-by-step explanation:

Ratios are just fractions. That being said, you also have part of a fraction. You know that the colorado flag is in 2:3, and 12 feet long is according to that ratio; it equals each other.

Make the equation.

\frac{2}{3}  = \frac{x}{12}

Now isolate x (in order to solve for it)

12 * \frac{2}{3}  = \frac{x}{12}*12\\8 = x

x= 8

The height is 8.

8/12 = 2/3 ✅

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A line passes through the point (4,1) and has a slope of 5/4
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Maths functions question
yarga [219]

Answer:

a)  OA = 1 unit

b)  OB = 3 units

c)  AB = √10 units

Step-by-step explanation:

<u>Given function</u>:

g(x)=2^x

<h3><u>Part (a)</u></h3>

Point A is the y-intercept of the exponential curve (so when x = 0).

To find the y-value of Point A, substitute x = 0 into the function:

\implies g(0)=2^0=1

Therefore, A (0, 1) so OA = 1 unit.

<h3><u>Part (b)</u></h3>

If BC = 8 units then the y-value of Point C is 8.

The find the x-value of Point C, set the function to 8 and solve for x:

\begin{aligned}f(x) & = 8 \\\implies 2^x & = 8\\2^x & = 2^3\\\implies x &= 3\end{aligned}

Therefore, C (3, 8) so Point B is (3, 0).  Therefore, OB = 3 units.

<h3><u>Part (c)</u></h3>

From parts (a) and (b):

  • A = (0, 1)
  • B = (3, 0)

To find the length of AB, use the distance between two points formula:

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

\textsf{where }(x_1,y_1) \textsf{ and }(x_2,y_2)\:\textsf{are the two points.}

Therefore:

\implies \sf AB=\sqrt{(x_B-x_A)^2+(y_B-y_A)^2}

\implies \sf AB=\sqrt{(3-0)^2+(0-1)^2}

\implies \sf AB=\sqrt{(3)^2+(-1)^2}

\implies \sf AB=\sqrt{9+1}

\implies \sf AB=\sqrt{10}\:\:units

5 0
2 years ago
5(x+2)-7=-32 solve variable. include steps, also check your answer!
Vika [28.1K]

Answer:

Step-by-step explanation:

5x+10-7=-32

5x+3=-32

5x+3-3=-32-3

5x=-35

X=-35/5

X=-7

Check:

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4 0
3 years ago
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The graph of g(x)=(0.5)x+4 is shown. Which equation is an asymptote of this function? y = 0 y = 4 x = 4 x = 0
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we are given

g(x)=(0.5)^x+4

we can see that

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now, we will find horizontal asymptote

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\lim_{x \to \infty} g(x)= (\lim_{x \to \infty} (0.5)^x+\lim_{x \to \infty} 4 )

\lim_{x \to \infty} g(x)= 0+4

so, we get

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y= 4............Answer

3 0
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