2,825 i am almost sure this is the right answer i apologize if not
Answer:
89.1° or -1.4°
Step-by-step explanation:
1. Location:
You are on the Mont-Saint-Jean escarpment, near the Belgian town of Waterloo.
The French troops are about 50 m below you and 1.2 km distant.
2. Finding the firing angle
Data:
R = 1200 m
u = 600 m/s
h = -50 m (the height of the target)
a = 9.8 m/s²
We have two conditions.
Horizontal distance
(1) 1200 = 600t cosθ
Vertical distance
(2) -50 = 600t sinθ - 4.9t²
Divide each side of (1) by 600cosθ.

Substitute (3) into (2)

Recall that
(5) sec²θ = 1/cos²θ = tan²θ + 1
Substitute (5) into (4)

Set up a quadratic equation

Solve for θ
Use the quadratic formula.
tanθ = 61.249 or -0.025
θ = arctan(61.249) = 89.1° or
θ = arctan(-0.025) = -1.4°
Answer:
I believe it’s the 3rd one.
Explanation:
It’s the only graph where it looks like (2.5,5) was graphed.
If I’m getting this right the equation is: 0.00045 - 2.5 x 10 - 5? The dot in between 2.5 and 10 indicates a multiplication sign
So...
0.00045 - (2.5 x 10) - 5
0.00045 - 25 - 5
= -29.9999 -> -30
Answer: A
Step-by-step explanation:
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