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inessss [21]
3 years ago
15

Write an equation for a line perpendicular to y= -4x +2 and passing through the point (12,6)

Mathematics
1 answer:
gtnhenbr [62]3 years ago
5 0

Answer:

y=\frac{1}{4} x+3

Step-by-step explanation:

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12/45 =¿ fraccion mixta ,propia o impropia?<br><br> 24/5=¿fraccion mixta,propia o impropia?
Aloiza [94]
12/45 = fracción propia24/5 = fracción impropia
8 0
3 years ago
Cheyanne is saving for a car. The amount she has saved for the car, f(x), can be represented by the function f(x) = 65x + 750, w
lisabon 2012 [21]
She initially had $700 saved before working
6 0
3 years ago
How to find an equation for a line through two given points?​
xz_007 [3.2K]

Answer:

The equation of the line is: y = 0.6x + 0.6

Step-by-step explanation:

Equation of a line:

The equation of a line has the following format:

y = mx + b

In which m is the slope and b is the y-intercept.

Two points:

We have these following two points in this exercise:

x = -6, y = -3, so (-6,-3)

x = 4, y = 3, so (4,3)

Finding the slope:

Given two points, the slope is given by the change in y divided by the change in x.

Change in y: 3 - (-3) = 3 + 3 = 6

Change in x: 4 - (-6) = 4 + 6 = 10

So

m = \frac{6}{10} = 0.6

Then

y = 0.6x + b

Finding b:

We replace one of the points in the equation to find b. I will use (4,3).

y = 0.6x + b

3 = 0.6*4 + b

2.4 + b = 3

b = 0.6

The equation of the line is: y = 0.6x + 0.6

4 0
3 years ago
Find the quadratic function y=​f(x) whose graph has a vertex ​(−3​,4​) and passes through the point ​(−7​,0). Write the function
olganol [36]

Answer:

Step-by-step explanation:

This is a parabola since a quadratic is a parabola.  The standard form for a parabola is y = ax² + bx + c

but before we do that, we will use the vertex form, since it will make our work easier at the beginning.  

First and foremost, when we plot the vertex and the given point, the vertex is higher up than is the point; that means that this parabola opens upside down, and its vertex form will be

y=-|a|(x - h)² + k

The absolute value is out in front of the a, so we know that the value of a is positive, but the quadratic itself is negative (upside down) and we will find that math takes care of that negative that needs to be out front.  So we need to solve for a by filling in the x, y, h, and k values from the point and the vertex:  x = -7, y = 0, h = -3, k = 4

0 = a(-7 - (-3))² + 4 and

0 = a(-7 + 3)² + 4 and

0 = a(-4)² + 4 and

0 = a(16) + 4 and

0 = 16a + 4 and

-4 = 16a so

a=-\frac{1}{4}

Now that we know a, we can plug it back into the vertex form and then put it into standard form from there.

y=-\frac{1}{4}(x+3)^2+4

Now we will FOIL out what's inside the parenthesis to get

y=-\frac{1}{4}(x^2+6x+9)+4

Simplify by distributing the -1/4 into the parenthesis:

y=-\frac{1}{4}x^2-\frac{3}{2}x-\frac{9}{4}+4

Combine like terms to get

y=-\frac{1}{4}x^2-\frac{3}{2}x+\frac{7}{4}

And there you go!

5 0
3 years ago
What is the area of an isosceles trapezoid, if its shorter base has length of 18 cm, the length of the altitude is 9 cm, and the
padilas [110]

The formula for the area of a triangle of base b and altitude h is A = (1/2)(b)(h).

Here, b = 18 cm and h = 9 cm.  Thus, the desired area is:

        (18 cm)(9 cm)

A = ----------------------- = 81 cm^2

                  2

This problem gives you more info than is needed to solve it.  The area of the given triangle is 81 cm^2.

5 0
3 years ago
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