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inessss [21]
2 years ago
15

Write an equation for a line perpendicular to y= -4x +2 and passing through the point (12,6)

Mathematics
1 answer:
gtnhenbr [62]2 years ago
5 0

Answer:

y=\frac{1}{4} x+3

Step-by-step explanation:

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X2 + 4x -9 = (x + a)? +b<br> Find the value of a and the value of b.<br> a =<br> b=<br> ?
Burka [1]

Step-by-step explanation:

x² + 4x - 9

= (x + 2)² - 13

a = 2, b = -13.

4 0
3 years ago
Solve the equation 15p2 + 7p − 4 = 0 by completing the square.
natulia [17]

Answer:

p=0 or p=-7/15

Step-by-step explanation:

15p2+7p=0

p(15p+7)=0

p=0 or 15p+7=0

4 0
1 year ago
Write 3x^2-18x-6 in vertex form
Vedmedyk [2.9K]
The standard form of a quadratic equation is \displaystyle{ y=ax^2+bx+c, while the vertex form is:

                      y=a(x-h)^2+k, where (h, k) is the vertex of the parabola.

What we want is to write \displaystyle{ y=3x^2-18x-6 as y=a(x-h)^2+k

First, we note that all the three terms have a factor of 3, so we factorize it and write:

\displaystyle{ y=3(x^2-6x-2).


Second, we notice that x^2-6x are the terms produced by (x-3)^2=x^2-6x+9, without the 9. So we can write:

x^2-6x=(x-3)^2-9, and substituting in \displaystyle{ y=3(x^2-6x-2) we have:

\displaystyle{ y=3(x^2-6x-2)=3[(x-3)^2-9-2]=3[(x-3)^2-11].

Finally, distributing 3 over the two terms in the brackets we have:

y=3[x-3]^2-33.


Answer: y=3(x-3)^2-33
6 0
3 years ago
Write the slope intercept equation of the function f whose graph satisifies the given conditions. The graph of f passes through
MrMuchimi
  • Let's find slope first.

  • (1,-2)
  • (-8,6)

\\ \sf\longmapsto m=\dfrac{6+2}{-8-1}

\\ \sf\longmapsto m=\dfrac{8}{-9}

Slope intercept form

\\ \sf\longmapsto y=mx+b

\\ \sf\longmapsto y=-\dfrac{8}{9}x-2

3 0
2 years ago
Tyrone is buying candy by the pound to stuff into a piñata. Her purchased 14 pounds of candy for $12. How much is the cost of on
Deffense [45]
I believe the answer is


26

sorry if wrong


if not an answer choice then 168.
4 0
3 years ago
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