Solve for x: 4(x + 2) = 3(x - 2) -2 -4 -10 -14

Mathematics

1 answer:

m_a_m_a [10]4 years ago

3 0

Answer:

D. -14

Step-by-step explanation:

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Help plz

Vlad [161]

I think the answer is C hope it helps

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3 years ago

What is the solution to the equation below?

olasank [31]

A. W=2/12

4w=2/3

(Divide both sides of the equation by 4)

4w/4=2/3/4

(Any expression divided by it’s self is 1)

w=2/3/4

(To divide a fraction by a number, multiply by it’s reciprocal)

w=2/3 • 1/4

(Reduce the numbers with the greatest common factor 2)

w= 1/3 • 1/2

(Multiply the fractions)

w= 1/3 • 1/2= 1/6

1/6=2/12

3 0

3 years ago

Make q the subject of the formula <img src="https://tex.z-dn.net/?f=%20%5Cfrac%7Ba%7D%7Bp%20%7D%20%20-%20%20%5Cfrac%7Bb%7D%7

alukav5142 [94]

Answer:

q=bp

a- cp

Step-by-step explanation:

a - b = c

p q

Multiply through by pq

qa - bp = cpq

qa - cpq = bp

q [a-cq] = bp

q= bp

a-cp

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3 years ago

A man was sitting with his feet up on a desk. He turned his head when Stanley and the guard entered, but otherwise didn't move.

stellarik [79]

The answer I got was He is strict.

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4 years ago

Read 2 more answers

Simplify completely..........

vitfil [10]

Answer:

$\frac{x}{x-1}$

Step-by-step explanation:

$\frac{3x^2 - 1}{x^2 - 1} - \frac{2x + 1}{x + 1}$ $[ \ x^ 2- 1 = (x-1)(x + 1) \ ]$

$= \frac{3x^2 - 1}{(x-1)(x + 1 )} - \frac{2x + 1}{x + 1}\\\\=\frac{(3x^2 - 1)-(2x + 1)(x-1)}{(x + 1)(x-1)}$ $[\ Taking \ LCM \ ]$

$= \frac{(3x^2 - 1)- (2x^2 - 2x + x - 1)}{(x+1)(x-1)}\\\\=\frac{3x^2 - 1 - 2x^2 + x + 1 }{(x+1)(x-1)}\\\\=\frac{x^2 +x}{(x+1)(x-1)}\\\\=\frac{x(x+1)}{(x+1)(x-1)}\\\\=\frac{x}{x-1}$