All categories

3 years ago

Help!!!!! Find the volume of the cylinder

Mathematics

1 answer:

Mazyrski [523]3 years ago

7 0

Answer:

V= 452.16

Step-by-step explanation:

V= πr^2h

V= π6^2(4)

V= π x 36 x 4

V= π x 144

π= 3.14

V= 3.14 x 144

V= 452.16

You might be interested in

190 10 AK-001 in 80 201 70, 30, 11516 이 11 213145 1기 60 40 50

Sav [38]

Answer:

Hjejejjwjejekehegdkdkhdjdsjjdkd

Step-by-step explanation:

4 0

3 years ago

He scored 3 goals at Saturdays gams and scored 5 goals in yesterdays game . What is his percent of increase?

trasher [3.6K]

Answer: his percent of increase = 66.66%

Step-by-step explanation:

percent of increase = Increase/ Previous goal x 100

Previous goal = 3 goals

Yesterday's goal = 5 goals

Percent of increase = (5-3) / 3 x 100

=2/3 x 100

=0.6666 x 100

=66.66%

5 0

3 years ago

.(3x+1)(x-3) Binomial

Dafna11 [192]

Answer:

3x^2−8x−3

Step-by-step explanation:

(3x+1)(x−3)

=(3x+1)(x+−3)

=(3x)(x)+(3x)(−3)+(1)(x)+(1)(−3)

=3x^2−9x+x−3

=3x^2−8x−3

5 0

3 years ago

Aaron's car used 3- gallons of gas when

monitta

We want to find miles per gallon. Another way of saying miles per gallon is miles/gallon. So we will plug the numbers into this equation:

60 miles/3 gallons = 20 miles/gallon

This is because 60/3=20.

I hope this makes sense.

4 0

3 years ago

Read 2 more answers

Naval intelligence reports that 4 enemy vessels in a fleet of 17 are carrying nuclear weapons. If 9 vessels are randomly targete

icang [17]

Answer:

0.7588 = 75.88% probability that more than 1 vessel transporting nuclear weapons was destroyed

Step-by-step explanation:

The vessels are destroyed without replacement, which means that the hypergeometric distribution is used to solve this question.

Hypergeometric distribution:

The probability of x successes is given by the following formula:

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

In which:

x is the number of successes.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

Combinations formula:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

In this question:

Fleet of 17 means that $N = 17$

4 are carrying nucleas weapons, which means that $k = 4$

9 are destroyed, which means that $n = 9$

What is the probability that more than 1 vessel transporting nuclear weapons was destroyed?

This is:

$P(X > 1) = 1 - P(X \leq 1)$

In which

$P(X \leq 1) = P(X = 0) + P(X = 1)$

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

$P(X = 0) = h(0,17,9,4) = \frac{C_{4,0}*C_{13,9}}{C_{17,9}} = 0.0294$

$P(X = 1) = h(1,17,9,4) = \frac{C_{4,1}*C_{13,8}}{C_{17,9}} = 0.2118$

Then

$P(X \leq 1) = P(X = 0) + P(X = 1) = 0.0294 + 0.2118 = 0.2412$

$P(X > 1) = 1 - P(X \leq 1) = 1 - 0.2412 = 0.7588$

0.7588 = 75.88% probability that more than 1 vessel transporting nuclear weapons was destroyed

8 0

3 years ago