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Dmitrij [34]
3 years ago
14

Solve the system of linear equations by elimination −2x+3y=7 and 5x+8y=−2

Mathematics
1 answer:
Charra [1.4K]3 years ago
7 0

Hey!

Here's how you would solve it with elimination:

-2x + 3y = 7

5x + 8y = -2

Multiply first equation by 5 and the second one by 2:

-10x + 15y = 35

10x + 16y = -4

Add the two equations:

-10x + 15y = 35

+

10x + 16y = -4

------------------------

31y = 31

y = 1

Plug this back into one of the original equation:

5x + 8y = -2

5x + 8(1) = -2

5x + 8 = -2

5x = -10

x = -2

Now you have your answer:

y = 1

x = -2

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4y-5x=-8
Dovator [93]

Answer:

4y−5x=−8

Step 1: Add -4y to both sides.

−5x+4y+−4y=−8+−4y

−5x=−4y−8

Step 2: Divide both sides by -5.

−5x

−5

=

−4y−8

−5

x=

4

5

y+

8

5

Answer:

x=

4

5

y+

8

5

Step-by-step explanation:

3 0
3 years ago
Simplify : this problem
Nikitich [7]
Answer:
\frac{(7r + 1)(7r - 1)}{7r}
6 0
3 years ago
Moe and Larry each need to raise $200 to go on a trip with their school band.
svlad2 [7]

<u><em>Moe Larry</em></u>

<u><em>35 + 20x 60 + 10x</em></u>

<u><em></em></u>

<u><em>35 + 20x = 60 + 10x</em></u>

<u><em>(show work)</em></u>

<u><em>x = 2.5</em></u>

<u><em></em></u>

<u><em>Moe and Larry will have the same amount of money in their savings accounts after 2.5 weeks.</em></u>

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3 0
2 years ago
How do I solve 2m + n = 2 and 3m - 2n = 3 using substitution?
Leona [35]

\huge \boxed{\mathbb{QUESTION} \downarrow}

  • Solve 2m + n = 2 and 3m - 2n = 3 using substitution.

\large \boxed{\mathfrak{Answer \: with \: Explanation} \downarrow}

We can use the substitution method to solve linear equations of this form. Let's solve for m & n.

\left. \begin{array}  { l  }  { 2 m + n = 2 } \\ { 3 m - 2 n = 3 } \end{array} \right.

To solve a pair of equations using substitution, first solve one of the equations for one of the variables. Then substitute the result for that variable in the other equation.

2m+n=2, \: 3m-2n=3

Choose one of the equations and solve it for m by isolating m on the left-hand side of the equal sign.

2m+n=2

Subtract n from both sides of the equation.

2m=-n+2

Divide both sides by 2.

m=\frac{1}{2}\left(-n+2\right)  \\

Multiply 1/2 times -n+2.

m=-\frac{1}{2}n+1  \\

Substitute -\frac{n}{2}+1\\ for m in the other equation, 3m-2n=3.

3\left(-\frac{1}{2}n+1\right)-2n=3  \\

Multiply 3 times -\frac{n}{2}+1\\.

-\frac{3}{2}n+3-2n=3  \\

Add -\frac{3n}{2}\\ to -2n.

-\frac{7}{2}n+3=3  \\

Subtract 3 from both sides of the equation.

-\frac{7}{2}n=0  \\

Divide both sides of the equation by -\frac{7}{2}\\, which is the same as multiplying both sides by the reciprocal of the fraction.

\large \underline{\underline{ \bf \: n=0 }}

Substitute 0 for n in m=-\frac{1}{2}n+1\\. Because the resulting equation contains only one variable, you can solve for m directly.

\large \underline{ \underline{\bf \: m=1 }}

The system is now solved.

\huge \boxed{ \boxed{ \bf \: m=1, \: n=0 }}

4 0
3 years ago
Help please I will mark brainliest!
ruslelena [56]

Answer:

multiply 8 x 4=22

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
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