The expression into a single logarithm is ![log[(x)^{10}][(2)^{30}]](https://tex.z-dn.net/?f=log%5B%28x%29%5E%7B10%7D%5D%5B%282%29%5E%7B30%7D%5D)
Step-by-step explanation:
Let us revise some logarithmic rules
∵ 10 log(x) + 5 log(64)
- At first re-write 10 log(x)
∴ 10 log(x) = 
- Then re-write 5 log(64)
∴ 5 log(64) = 
∴ 10 log(x) + 5 log(64) =
+ 
- Use the 3rd rule above to make it single logarithm
∵
+
= ![log[(x)^{10}][(64)^{5}]](https://tex.z-dn.net/?f=log%5B%28x%29%5E%7B10%7D%5D%5B%2864%29%5E%7B5%7D%5D)
∴ 10 log(x) + 5 log(64) = ![log[(x)^{10}][(64)^{5}]](https://tex.z-dn.net/?f=log%5B%28x%29%5E%7B10%7D%5D%5B%2864%29%5E%7B5%7D%5D)
∵ 64 = 2 × 2 × 2 × 2 × 2 × 2
∴ We can write 64 as 
∴ 
- Multiply the two powers of 2
∴ 
∴ 10 log(x) + 5 log(64) = ![log[(x)^{10}][(2)^{30}]](https://tex.z-dn.net/?f=log%5B%28x%29%5E%7B10%7D%5D%5B%282%29%5E%7B30%7D%5D)
The expression into a single logarithm is ![log[(x)^{10}][(2)^{30}]](https://tex.z-dn.net/?f=log%5B%28x%29%5E%7B10%7D%5D%5B%282%29%5E%7B30%7D%5D)
Learn more:
You can learn more about the logarithmic functions in brainly.com/question/11921476
#LearnwithBrainly
Answer:
5/24
Step-by-step explanation:
Start with the first part of the probelm 5/6 - 2/3
You need to find a common denominator of 6 and 3
common denominator= 6
so change 2/3 to 4/6
now you can subtract the top values
5/6-4/6
5-6=1
keep the denominator the same
= 1/6
Now divide 1/6 by 4/5
to divide you are going to multiply by the reciprocal so instead of 4/5 we are going to flip it to 5/4
1/6 x 5/4
5x1=5 and 6x4=24
= 5/24
Square root of 16 because it equals to 4 which is a rational number
101 + d = 180
d = 79
91 + c = 180
c = 89
95 + a = 202
a = 107
b + 107 = 178
b = 71
Answer:
He can select a row of the random number table and read 20 single digits between 1 and 5. He will record the number of digits that are a 1.
Step-by-step explanation:
edge 2022