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Darina [25.2K]
3 years ago
13

Natalia and Riley hike 10 6/11 miles. In one day, Ricardo hiked to 2 3/4 times as far as Natalia and Riley hiked. how far did he

hike?
Mathematics
1 answer:
Maksim231197 [3]3 years ago
7 0

Answer:

Ricardo hiked 29 miles.

Step-by-step explanation:

10 6/11 x 2 3/4

convert

116/11 x 11/4 = 1276/44

1276/44 = 29

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The answer is 52+7x I hope this helps
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Which of equation represents a function? A. x2 + y2 = 9 B. {(4, 2), (4, –2), (9, 3), (9, –3)} C. x = 4. 2x + y = 5
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The answer to your questions is B. {(4, 2), (4, –2), (9, 3), (9, –3)} because you don't have a repeat of a number the X side which is your output. I hope that this is the answer that you were looking for and it has helped you.
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3 years ago
The scale for a map is 20 miles = 1/2 inch. The distance between two towns on the map is 3 3/4 inches. What is the actual distan
zubka84 [21]

Answer:

150 miles

Step-by-step explanation:

If 1/2 of an inch is 20 miles, we can assume that 1/4 of an inch is 10 miles, since half of 1/2 is 1/4 and 1/2 of 20 is 10.

Equipped with this information, we can divide 3 by 1/2 or multiply 3 by the reciprical, 2/1 to get how much we should multiply 20 by.

3*2=6

20*6=120

Then we can multiply 10 by 3 and add that on our answer, since there are still 3/4s left and 1/4=10 miles.

10*3=30

120+30=150

The actual distance is 150 miles.

Hope this helps!

4 0
3 years ago
For a normal distribution,
Anni [7]

Answer:

1.282, -0.5244,...

Step-by-step explanation:

We know that Z is a standard normal variate with mean =0, and std dev =1

a) z-score separates the highest 10% from the rest of the scores

= 90th percentile = 1.282

b) z-score separates the lowest 30% from the rest of the scores

= 30th percentile = -0.5244

c) z-score separates the lowest 40% from the rest of the scores

= 40th percentile = -0.2533

d) z-score separates the lowest 20% from the rest of the score

=20th percentile = -0.8416

7 0
3 years ago
The sample space of a random experiment is {a, b, c, d, e} with probabilities 0.1, 0.1, 0.2, 0.4, and 0.2 respectively. Let A de
antoniya [11.8K]

Answer:

a) P(A) =P(a)+P(b) +P(c)= 0.1+0.1+0.2 = 0.4

b) P(B) =P(c) +P(d)+P(e)=0.2+0.4+0.2=0.8

c) P(A') = 1-P(A) =1-0.4=0.6

d) P(A \cup B) =0.4 +0.8-0.2 =1.0

e)  The intersection between the set A and B is the element c so then we have this:

P(A \cap B) = P(c) =0.2

Step-by-step explanation:

We have the following space provided:

S= [a,b,c,d,e]

With the following probabilities:

P(a) =0.1, P(b)=0.1, P(c) =0.2, P(d)=0.4, P(e)=0.2

And we define the following events:

A= [a,b,c], B=[c,d,e]

For this case we can find the individual probabilities for A and B like this:

P(A) = 0.1+0.1+0.2 = 0.4

P(B) =0.2+0.4+0.2=0.8

Determine:

a. P(A)

P(A) =P(a)+P(b) +P(c)= 0.1+0.1+0.2 = 0.4

b. P(B)

P(B) =P(c) +P(d)+P(e)=0.2+0.4+0.2=0.8

c. P(A’)

From definition of complement we have this:

P(A') = 1-P(A) =1-0.4=0.6

d. P(AUB)

Using the total law of probability we got:

P(A \cup B) =P(A) +P(B)-P(A \cap B)

For this case P(A \cap B) = P(c) =0.2, so if we replace we got:

P(A \cup B) =0.4 +0.8-0.2 =1.0

e. P(AnB)

The intersection between the set A and B is the element c so then we have this:

P(A \cap B) = P(c) =0.2

8 0
3 years ago
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