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3 years ago

I need the RIGHT answer to this please. :)

Mathematics

2 answers:

Sveta_85 [38]3 years ago

8 0

The correct answer is A.

KATRIN_1 [288]3 years ago

3 0

A is the answer. It has no repeating x points buy it repeats on the y coordinate, which is okay. The answer is A just to say it again.

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What is the value of x for this question?

cestrela7 [59]

Answer:

Step-by-step explanation:

3x + 3

6 + 2x

3x + 2x = 5x

3 + 6 = 9

5x + 9

4 0

2 years ago

malik collects rare stamps and has a total of 212 stamps. he has 34 more domestic stamps than foreign stamps. let x represent th

valina [46]

<span>x = number of domestic stamps

y = number of foreign stamps

Malik collects rare stamps and has a total of 212 stamps.

=> x + y = 212

he has 34 more domestic stamps than foreign stamps.

=> x = y + 34

which equation represents the total number of stamps malik collected?

x + y = 212

which equation represents the difference in the number of foreign and domestic stamps malik collected?

x - y = 34

which system of linear equations represents the situation?

x + y = 212
x - y = 34
</span>

8 0

3 years ago

Read 2 more answers

1/3 X 12 = 12 X ___ = __

valkas [14]

1/3=4 hop this help you

8 0

2 years ago

126 = -61-7 - 2n) ?

Lilit [14]

Answer:

X=-97

Step-by-step explanation:

8 0

2 years ago

Read 2 more answers

The quadratic function g(x) = a.ca + bx+c has the

Mumz [18]

<em>The value of b is 14 and the value of c is 65</em>

<h2>Explanation:</h2>

The quadratic function is a function of the form:

$f(x)=ax^2+bx+c$

Here we know that the leading coefficient $a=1$ so we reduce our equation to:

$g(x)=x^2+bx+c$

The roots are those values at which $g(x)=0$

So:

$x^2+bx+c=0 \\ \\ First \ root: \\ \\ (-7+4i)^2+b(-7+4i)+c=0 \\ \\ (-7)^2-2(7)(4i)+(4i)^2-7b+4bi+c=0 \\ \\ 49-56i+16i^2-7b+4bi+c=0 \\ \\ \\ Simplifying: \\ \\ 49-56i+16(-1)-7b+4bi+c=0 \\ \\ 49-56i-16-7b+4bi+c=0 \\ \\ 33-56i-7b+4bi+c=0 \\ \\ \\$

$Second \ root: \\ \\ (-7-4i)^2+b(-7-4i)+c=0 \\ \\ (-1)^2(7+4i)^2+b(-7-4i)+c=0 \\ \\ (7)^2+2(7)(4i)+(4i)^2-7b-4bi+c=0 \\ \\ 49+56i+16i^2-7b-4bi+c=0 \\ \\ \\ Simplifying: \\ \\ 49+56i+16(-1)-7b-4bi+c=0 \\ \\ 49+56i-16-7b-4bi+c=0 \\ \\ 33+56i-7b-4bi+c=0$

So we have:

$(1) \ 33-56i-7b+4bi+c=0 \\ \\ (2) \ 33+56i-7b-4bi+c=0 \\ \\ \\ Subtract \ 2 \ from: \\ \\ 33-56i-7b+4bi+c-(33+56i-7b-4bi+c)=0 \\ \\ 33-56i-7b+4bi+c-33-56i+7b+4bi-c=0 \\ \\ \\ Combine \ like \ terms: \\ \\ 33-33-56i-56i-7b+7b+4bi+4bi+c-c=0 \\ \\ -112i+8bi=0 \\ \\ Isolating \ b: \\ \\ b=\frac{112i}{8i} \\ \\ \boxed{b=14}$

Finding c from (1):

$33-56i-7b+4bi+c=0 \\ \\ \\ Substituting \ b: \\ \\ 33-56i-7(14)+4(14)i+c=0 \\ \\ 33-56i-98+56i+c=0 \\ \\ -65+c=0 \\ \\ \boxed{c=65}$

<h2>Learn more:</h2>

Complex conjugate: brainly.com/question/2137496

#LearnWithBrainly

5 0

3 years ago