The answer is: "
125.6 sq units " ; or, write as: "
125.6 units² " .
____________________________________________________Explanation:___________________________________To solve for the "area of the shaded region" :
___________________________________1) We find the area of the: "circle with radius of 11" ; that is, the entire circle that includes the entire outer circle—incorporating the shaded region AND non-shaded region. Record that value.
________________________________________________________2) Then we find the area of the: "circle with radius of 9" ; that is; the entire "inner circle" that is "inside the shaded region". Record that value.
________________________________________________3) Then, we take the [area of the "circle with radius of 11"] ; and from that value, subtract the: "[area of the circle with radius of 9"] ;
to get the value of the "<em><u>
area of the shaded region</u></em>" {that is, the "<em><u>
area of the blue ring</u></em>"} .
________________________________________________Let us begin:1) Find the area of the: "circle with radius of 11" ;
The formula for the area, "A" of a circle is:
→ " A =
r² " ;
in which: " A = area of the circle" (in "units² " ; or "square units" ; or "sq units") ;
"
= 3.14 " (approximation) ;
" r = radius = 11 " ;
____________________________________________→ Plug in these values to solve for the "area of the circle with radius of 11" :
→ A =
r² ;
A = (3.14) * 11² ;
A = (3.14) * 11 * 11 ;
A = (3.14) * 121 ;
A = 379.94 units²__________________________________________________2) Now, let us find the area of the: "circle with radius of 9" ;
The formula for the area, "A" of a circle is:
→ " A =
r² " ;
in which: " A = area of the circle" (in "units² " ; or "square units" ; or "sq units") ;
"
= 3.14 " (approximation) ;
" r = radius = 9 " ;
____________________________________________→ Plug in these values to solve for the "area of the circle with radius of 9" :
→ A =
r² ;
A = (3.14) * 9² ;
A = (3.14) * 9 * 9 ;
A = (3.14) * 81 ;
A = 254.34 units²______________________________________________________2) Now, let us subtract the "area of the circle with radius of 9" ; FROM:
the "area of the circle with radius of 11" ;
_____________________________________________________ 3 7 9. 94 units² — 2 5 4. 34 units² ________________________ 1 2 5 . 60 units²______________________________________________________The answer is: "
125.6 sq units " ; or, write as: "
125.6 units² " .
______________________________________________________