All Real Numbers is the domain
Let's find the discriminant of <span>x^2+9x+14=0. Here, a=1, b=9 and c=14.
The discriminant is b^2-4ac. Substituting the above numeric values,
9^2-4(1)(14) = 81-56 = 25
The sqrt of 25 is 5. Thus, your polynomial has two unequal, real roots.
Off the point example: If the discriminant were zero, your poly would have two real, equal roots.</span>
Answer:
yes correct
Step-by-step explanation:
given
5x ≥ 3x + 4 ( subtract 3x from both sides )
2x ≥ 4 ( divide both sides by 2 )
x ≥ 2 ← is the solution to the inequality
The only value greater than 2 is 3
(-1,-2) and (-1,4)
so these have same x values, but different y values, so these are on differnt sidef of circle
distanc between them is 6
6/2=3
radius=3
so move 3 units up from (-1,-2)
(-1,1)
so
if center is (h,k) and radius is r then
(x-h)^2+(y-k)^2=r^2
(-1,1) is center and r=3
(x-(-1))^2+(y-1)^2=3^2
(x+1)^2+(y-1)^2=9
Answer:
1
Step-by-step explanation:
the y-intercept is -1 since 4-3 is 1
