9514 1404 393
Answer:
382 square units
Step-by-step explanation:
The central four rectangles down the middle of the net are 9 units wide, and alternate between 8 and 7 units high. Then the area of those four rectangles is ...
9(8+7+8+7) = 270 . . . square units
The rectangles making up the two left and right "wings" of the net are 8 units high and 7 units wide, so have a total area of ...
2×(8)(7) = 112 . . . square units
Then the area of the figure computed from the net is ...
270 +112 = 382 . . . square units
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<em>Additional comment</em>
You can reject the first two answer choices immediately, because they are odd. Each face will have an area that is the product of integers, so will be an integer. There are two faces of each size, so <em>the total area of this figure must be an even number</em>.
You may recognize that the dimensions are 8, 8+1, 8-1. Then the area is roughly that of a cube with dimensions of 8: 6×8² = 384. If you use these values (8, 8+1, 8-1) in the area formula, you find the area is actually 384-2 = 382. That area formula is A = 2(LW +H(L+W)).
When we look at an ordered pair, it will be presented as (x,y)
The first term, x (called the x-coordinate), will tell us how far we should count outwards from 0 (The Origin). The second term, y (called the y-coordinate), will tell us how far we will count outwards from our x coordinate.
I hope this helps! If you would like me to elaborate more just let me know:)
Answer:
Step-by-step explanation:
Use the volume of cube formula.
![\displaystyle\sqrt[3]{5.832} =s](https://tex.z-dn.net/?f=%5Cdisplaystyle%5Csqrt%5B3%5D%7B5.832%7D%20%3Ds)
<span>The term that you want is 5C2*p^2*q^3
representing 2 successes and 3 failures. This term's value is</span>
<span>(5C2)(0.5^5)
= 10*0.03125 = 0.3125 = P(2 successes in 5 trials) =31.3% </span>
A triangle, cut it straight down the middle and you get a triangle
