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3 years ago

Find the slope (3, 8) and (2, 10)

Mathematics

2 answers:

timama [110]3 years ago

6 0

Answer:

m = -2

Step-by-step explanation:

polet [3.4K]3 years ago

4 0

Answer:

m = -2

Step-by-step explanation:

Let (x1 , y1 ) = ( 3 , 8) and (x2 , y2 ) = ( 2 , 10)

Now

slope (m)

= y2 - 1 / x2 - x1

= 10 - 8 / 2-3

= - 2

hope it helps :)

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The exponential function f(x) = 3(5)x grows by a factor of 25 between x = 1 and x = 3. What factor does it grow by between x = 5

Delvig [45]

Answer:

B) 25

Step-by-step explanation:

Given exponential function:

$f(x)=3(5)^x$

The growth factor between $x=1$ and $x=3$ is 25.

To find the growth factor between $x=5$ and $x=7$

Solution:

The growth factor of an exponential function in the interval $x=a$ and $x=b$ is given by :

$G=\frac{f(b)}{f(a)}$

We can check this by plugging in the given points.

The growth factor between $x=1$ and $x=3$ would be calculated as:

$G=\frac{f(3)}{f(1)}$

$f(3)=3(5)^3$

$f(1)=3(5)^1$

Plugging in values.

$G=\frac{3(5)^3}{3(5)^1}$

$G=\frac{(5)^3}{(5)^1}$ (On canceling the common terms)

$G=(5)^{(3-1)}$ (Using quotient property of exponents $\frac{a^b}{a^c}=a^{(b-c)}$ )

$G=(5)^{2}$

∴ $G=25$

Similarly the growth factor between $x=5$ and $x=7$ would be:

$G=\frac{f(7)}{f(5)}$

$f(7)=3(5)^7$

$f(5)=3(5)^5$

Plugging in values.

$G=\frac{3(5)^7}{3(5)^5}$

$G=\frac{(5)^7}{(5)^5}$ (On canceling the common terms)

$G=(5)^{(7-5)}$ (Using quotient property of exponents $\frac{a^b}{a^c}=a^{(b-c)}$ )

$G=(5)^{2}$

∴ $G=25$

Thus, the growth factor remains the same which is =25.

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raketka [301]

Answer:

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Step-by-step explanation:

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MrRa [10]

Answer:

277.15 yds

Step-by-step explanation:

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2 years ago

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pantera1 [17]

6x-5y=17
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Hitman42 [59]

Answer:

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Step-by-step explanation:

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