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4 years ago

5 biscuits cost 40p altogether how much do 3 biscuits cost

2 answers:

7 0

If 5 biscuits cost 40p

1 biscuit would cost (40p divided by 5) 8p

8p multiplied by 3 (to get 3 biscuits) would cost 24p

3 biscuits cost 24p

AfilCa [17]4 years ago

6 0

We can divide 40 by 5 to get the cost of 1 biscuit, and we can multiply that to 3 to get our final answer. 40 / 5 = 8, and 8 x 3 = 24, so 3 biscuits cost 24p.

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3 years ago

The endpoints of a diameter of a circle are (6,2) and (−2,5) . What is the standard form of the equation of this circle?

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Answer:

The standard form of the given circle is

$(x-2)^2+(y-\frac{7}{2})^2=73$

Step-by-step explanation:

Given that the end points of a diameter of a circle are (6,2) and (-2,5);

Now to find the standard form of the equation of this circle:

The center is (h,k) of the circle is the midpoint of the given diameter

midpoint formula is $M=(\frac{x_{1}+x_{2}}{2},\frac{y_{1}+y_{2}}{2})$

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$M=(\frac{4}{2},\frac{7}{2})$

$M=(2,\frac{7}{2})$

Therefore the center (h,k) is $(2,\frac{7}{2})$

now to find the radius:

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$d=\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}$

$=\sqrt{(-2-6)^2+(5-2)^2}$

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$(x-2)^2+(y-\frac{7}{2})^2=(\sqrt{73})^2$

$(x-2)^2+(y-\frac{7}{2})^2=73$

Therefore the standard form of the given circle is

$(x-2)^2+(y-\frac{7}{2})^2=73$

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