Answer:
16+c
Step-by-step explanation:
Sum means we will have to add. When it says "sum of sixteen and c" it is telling us to add both sixteen and c together.
Answer:
18 minutes
Step-by-step explanation:
if you divide 109 by 6, ya get 18.166666-
Answer:

Step-by-step explanation:
<u>Linear Combination Of Vectors
</u>
One vector
is a linear combination of
and
if there are two scalars
such as

In our case, all the vectors are given in
but there are only two possible components for the linear combination. This indicates that only two conditions can be used to determine both scalars, and the other condition must be satisfied once the scalars are found.
We have

We set the equation

Multiplying both scalars by the vectors

Equating each coordinate, we get



Adding the first and the third equations:


Replacing in the first equation



We must test if those values make the second equation become an identity

The second equation complies with the values of
and
, so the solution is

We know that
When we have

Here ,
a is the leading coefficient
c is the constant term
so, we can compare it with

so, we get

so,
leading coefficient is 5
constant term is 6......................Answer