3 years ago

HELPP

Mathematics

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Aliun [14]3 years ago

5 0

Answer:

1 and 4

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What is the area of the trapezoid?

DanielleElmas [232]

Answer:

C) 100 m^2

Step-by-step explanation:

Area of a trapezoid= h*[(b1+b2)/2]

h=10

b1=8

b2=12

Therefore:

A=10*[(8+12)/2]

A=10*(20/2)

A=10*10

A=100

So the area of the trapezoid is 100 m^2

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Step-by-step explanation: last year

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Find the absolute maximum and minimum values of the following function on the given interval. If there are multiple points in a

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$f(x)=3\sin x+3\cos x\implies f'(x)=3\cos x-3\sin x$

$f$ has critical points where $f'=0$ :

$3\cos x-3\sin x=0\implies\cos x=\sin x\implies\tan x=1\implies x=\pm\dfrac\pi4+2n\pi$

where $n$ is any integer. We get solutions in the interval $\left[0,\frac\pi3\right]$ for $n=0$ , for which $x=\frac\pi4$ .

At this critical point, we have $f\left(\frac\pi4\right)=3\sqrt2\approx4.243$ .

At the endpoints of the given interval, we have $f(0)=3$ and $f\left(\frac\pi3\right)=\frac{3+3\sqrt3}2\approx4.098$ .

So we have the extreme values

$\max\limits_{x\in\left[0,\frac\pi3\right]}f=3\sqrt2$

$\min\limits_{x\in\left[0,\frac\pi3\right]}f=3$

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Answer:

the answer is 34.

Step-by-step explanation:

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The above questions answer is 8 and 14

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