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2 years ago

HELPP

Mathematics

1 answer:

Aliun [14]2 years ago

5 0

Answer:

1 and 4

2 and 3

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Please help me on this!

yanalaym [24]

Answer:

${9}^{ - 8}$

Step-by-step explanation:

$\frac{ {9}^{ - 5} }{ {9}^{3} }$

${9}^{ - 5 - (3)}$

${9}^{ - 5 + (- 3)}$

${9}^{ - 8}$

6 0

3 years ago

What is the equation of the line that passes through the point (-1, 4) and has a<br> slope of -5?

AfilCa [17]

Answer:

Step-by-step explanation:

y - 4 = -5(x + 1)

y - 4 = -5x - 5

y = -5x - 1

4 0

2 years ago

Answer please I am in school so I don’t want to be shed by a dum link

Bumek [7]

Answer:

Sorry if I got it wrong.

Step-by-step explanation:

You add them together then devide by 3 so 333.333333333 squar feet per gallon so the art room is 400 so I would say about 1.5 or close to that

6 0

2 years ago

A roof is shaped like a square pyramid. The base length is 10 meters and the slant height is 12 meters. What is the surface area

nasty-shy [4]

Surface area of square pyramid having square base side = 10 cm and slant height = 20 cm is 340 square meters

<u>Solution:</u>

Given that

Shape of the roof is square pyramid.

Base length of square pyramid roof = 10 meters

Slant height of square pyramid roof = 12 meters

Need to calculate the surface area of the roof

$\text { Surface area of square pyramid }=s^{2}+2 \times s \times l$

Where s is side of square base and l is slant height.

In our case s = 10 meters and l = 12 meters

On substituting the given values in formula we get

Surface area of square pyramid $=10^{2}+(2 \times 10 \times 12)=100+240=340 \text { meters }^{2}$

Hence surface area of square pyramid having square base side = 10 cm and slant height = 20 cm is 340 square meters.

6 0

3 years ago

Paul, a janitor must move a large shipment of books from the first floor to the fifth floor. The sign on the elevator reads "max

ololo11 [35]

Answer:

Pauld should place a maximum of 12 boxes in the elevator

Step-by-step explanation:

As in the sign is stated that the maximum weight that the elevator can carry is of 1000 pounds and each of the boxes of books weighs 80 pounds, and as he is not going to be inside the elevator you should divide the maximum weigh the elevator can carry by the weight of each box of books then you have

$Maximum number of boxes = \frac{1000}{80} = 12.5$

He can maximum ride 12 boxes and a half, but if the boxes can't be divides he can just carry 12 boxes, because if he carries 13 the weight in the elevator will be of 1040, that beats the maximum capacity of the elevator.

Then he can maximum place 12 boxes in the elevator

3 0

3 years ago