Question

5x^2+ 23x + 12Factoring ​

Answer 1

Answer:

$(5 x+ 3)(x + 4)$

Step-by-step explanation:

We want to factor

$5 {x}^{2} + 23x + 12$

By comparing to

$a {x}^{2} + bx + c$

We have a=5, b=23, c=12

ac=60

We split the middle term with 3x+20x, since 3×20=60

This implies that:

$5 {x}^{2} + 3x + 20x + 12$

Factor by grouping;

$x(5 x+ 3)+ 4(5x + 3)$

We collect common factors again;

$(5 x+ 3)(x + 4)$