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Greeley [361]
2 years ago
9

In a given quadrilateral, each side is parallel to its opposite side and the diagonals are not perpendicular. What could it be?

Mathematics
2 answers:
Assoli18 [71]2 years ago
5 0
Answer
<span>A. Rectangle
</span><span>D. Parallelogram

Explanation
The four choices are all quadrilaterals with with at least a pair of parallel sides. 
A rectangle, a square, and a rhombus have opposite sides been parallel. 
For a square and a rhombus, the diagonals are perpendicular. 

The diagonals of a rectangle and a parallelograms are not perpendicular. 
</span><span>
</span>
vesna_86 [32]2 years ago
3 0
There are two answers : A) Rectangle and D) Parallelogram. Both have sides that are parallel to each opposite side and their diagonals are not perpendicular. 
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Answer: 13 and 14

Step-by-step explanation: algbra

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2 years ago
3y &lt;= -2x+18
weeeeeb [17]

Answer:

  • A (-4, -3)
  • C (2, 4)
  • E (3, 2)

Step-by-step explanation:

It is convenient to use technology to plot the points and the functions to see what lies where. The first attachment shows such a plot.

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Of course, you can do the function evaluations. For example, testing answer B, we find ...

... 3·6 ≤ -2·1 +18 . . . . <em>false</em> for the first equation — not a solution

Checking all the points requires 10 function evaluations. When things get repetitive like that, I like to use a graphing calculator or spreadsheet.

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<em>Using a calculator</em>

The second attachment shows a calculator evaluating the viability of each point as a solution. The equations have been rearranged to ...

  • -2x -3y +18 ≥ 0
  • -x +4y +12 ≥ 0

This makes it easy to look at the evaluation results to see if the solution is viable or not.

The x-values of the points are entered into list L₁ and the y-values into L₂. The result of the first inequality above is in L₃ and the result for the second inequality is in L₄. Any negative value in L₃ or L₄ shows a point that is <u>not</u> part of the solution set. Points B and D fail to match problem requirements.

Points A, C, and E are in the solution set.

6 0
3 years ago
The factors of x cube -10x square -53x-42
Verdich [7]

Answer:

<em><u></u></em>x^3 - 10 x^2 -53x -42 = ( x + 1)(x + 3) (x - 14)<em><u></u></em>

Step-by-step explanation:

 x^3 - 10x^2 -53x - 42

The factors of 42 : ±1 , ±2 , ±3 , ±6, ±7, ±14, ±21 , ±42

<u>Using trial and error method we will find the first root of the polynomial.</u>

1 : ( 1 )³ - 10 ( 1 )² - 53 ( 1 ) - 42

     1 - 10 - 53 - 42  ≠ 0

   Therefore 1 is not a root

-1 : ( -1 )³ - 10 (- 1 )² - 53 (- 1 ) - 42

      - 1 - 10 + 53 - 42

       53 - 53 = 0

Therefore - 1 is a root of the polynomial.

Therefore ( x + 1) is a factor.

<u>Now by long division or by using synthetic division we can find other factors.</u>

<u>Synthetic Division :</u>

                             -1 | 1      -10       -53      - 42

                                | 0     - 1          11          42

                                |______________________

                                  1      - 11       - 42        0

Therefore ,

x^3 - 10 x^2 -53x -42 = ( x + 1)(x^2 - 11x +42)  ------ ( 1 )

<u>Next further factorize x² - 11x - 42</u>

   x² - 11x - 42

= x² -  14x + 3x - 42

=x(x - 14) + 3 (x - 14)

=(x + 3 )(x - 14)

Therefore ,

x^3 - 10 x^2 -53x -42 = ( x + 1)(x + 3) (x - 14)

4 0
2 years ago
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myrzilka [38]

Answer:

B

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cosA=12/20=3/5

6 0
3 years ago
Read 2 more answers
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LuckyWell [14K]
The answer would have to be D
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