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2 years ago

In a given quadrilateral, each side is parallel to its opposite side and the diagonals are not perpendicular. What could it be?

2 answers:

5 0

Answer
A. Rectangle
D. Parallelogram

Explanation
The four choices are all quadrilaterals with with at least a pair of parallel sides.
A rectangle, a square, and a rhombus have opposite sides been parallel.
For a square and a rhombus, the diagonals are perpendicular.

The diagonals of a rectangle and a parallelograms are not perpendicular.

vesna_86 [32]2 years ago

3 0

There are two answers : A) Rectangle and D) Parallelogram. Both have sides that are parallel to each opposite side and their diagonals are not perpendicular.

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2 years ago

Given that the commuter used public transportation, find the probability that the commuter had a commute of 60 6060 or more minu

AlladinOne [14]

Complete Question

The two-way table below gives the thousands of commuters in Massachusetts in 2015 by transportation method and one-way length of commute.

$\left|\begin{array}{c|c|c|c|c|c|c}$Transport Mode/Minutes&$Less than 15&15-29&30-44& 45-59&$60 or more &$Total\\---&---&---&---&---&---&---\\$Private vehicle & 636&908&590&257&256&2647\\$Public Transportation&9&54&96&62&108&329 \\$Other&115&70&23&7&7&222\\---&---&---&---&---&---&---\\$Total&760&1032&709&326&371 &3198 \end{array}\right|$

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$\dfrac{108}{329}$

Step-by-step explanation:

From the table above

Total Number of commuters who used public transportation=329

Number of commuters who spent 60 or more minutes on public transportation=108

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Given that a commuter used public transportation, the probability that the commuter had a commute of 60 or more minutes:

P ( 60 + minutes ∣ public transportation ) = $\dfrac{108}{329}$

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3 years ago