In a given quadrilateral, each side is parallel to its opposite side and the diagonals are not perpendicular. What could it be?
2 answers:
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Answer:
x = 5, x = 11
Step-by-step explanation:
Set f(x) = 0 and solve for x.
0 = (x -8)² -9
9 = (x -8)² . . . . . add 9
±√9 = x -8 . . . . . take the square root
±3 +8 = x . . . . . . . add 8
That is, ...
x = 8 -3 = 5 . . . . lesser x
x = 8 +3 = 11 . . . greater x
Given
To obtain the minimum value of y, we first take the derivative of y
The derivative of y is:
Equating
gives the minimum value we require.
Doing that, we have:
So that
Therefore, the minimum value is x = 3