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Yakvenalex [24]
3 years ago
9

A 25 kg circular disk has a diameter of 2.5 feet and a thickness of 2.5 cm. Find the density of the disk in kg/m3. Next, find th

e weight of the object. Then calculate the buoyant force on the disk if it is submerged under water. Finally, will the object sink or float?
Physics
1 answer:
Gre4nikov [31]3 years ago
3 0

Answer:

Assume that \rm g= 9.81\; N\cdot kg^{-1}; \rho(\text{Water}) = \rm 1000\;kg\cdot m^{-3}.

Density of the disk: approximately \rm 2.19\times 10^{3}\; kg\cdot m^{-3}.

Weight of the disk: approximately \rm 245\;N.

Buoyant force on the disk if it is submerged under water: approximately \rm 112\; N.

The disk will sink when placed in water.

Explanation:

Convert the dimensions of this disk to SI units:

  • Diameter: d = \rm 25\; inches = (25\times 0.3048)\; m = 0.762\;m.
  • Thickness h = \rm 2.5\; cm = (2.5\times 0.01)\; m = 0.025\;m.

The radius of a circle is 1/2 its diameter:

\displaystyle r = \rm \frac{1}{2}\times 0.762\;m = 0.381\; m.

Volume of this disk:

V(\text{disk}) = \pi\cdot r^{2}\cdot h = \pi\times 0.381^{2}\times 0.025 \approx 0.0114009\; m^{3}.

Density of this disk:

\displaystyle \rho(\text{disk}) = \frac{m}{V} = \rm \frac{25\; kg}{0.0114009\; m^{3}} = 2.19\times 10^{3}\;kg\cdot m^{-3}.

\rho(\text{disk}) >\rho(\text{water}) indicates that the disk will sink when placed in water.

Weight of the object:

W(\text{disk}) = m\cdot g = \rm 25\times 9.81 = 245.25\; N.

The buoyant force on an object in water is equal to the weight of water that this object displaces. When this disk is submerged under water, it will displace approximately \rm 0.0114009\; m^{3} of water. The buoyant force on the disk will be:

\begin{aligned}F(\text{buoyant force}) &= W(\text{Water Displaced}) \\& = \rho\cdot V(\text{Water Displaced})\cdot g\\ & = \rm 1\times 10^{3}\; kg\cdot m^{-3}\times 0.0114009\; m^{3}\times 9.81\; N\cdot kg^{-1}\\ &\approx \rm 112\; N\end{aligned}.

The size of this disk's weight is greater than the size of the buoyant force on it when submerged under water. As a result, the disk will sink when placed in water.

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