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3 years ago

Lab - What Happens When Chemicals React?

1 answer:

8 0

Well, for name and date you'll put your own name and date. I can't do it for you cause I need to know what you are doing but,I can help. Title of lab put the title,Summary of Research: Just put basically in 2-3 sentences what the research is about.

Purpose/Objectives:Put the purpose like what it does, or what it's supposed to do.

Hypothesis: Then these I can't help without knowing what you are using ;/

Experimental Design:
Independent Variable:
Dependent Variable:
Control Group:
Constants (controlled conditions):

Materials: Just put what it contains.
Procedure: Now, for this just put what you need to do.
Results and Analysis: Then what you get after you do it.
Observations: What you have seen while you been doing this.
Data: just the things you know bout this.
Graph of Results: What it ends up like having.
Analysis Questions: Just questions about the chemicals
Conclusion: Just the ending a couple of sentences about what you've learned the chemicals etc...

Hope this help!

You might be interested in

Convert 6.95×105 cal to joules. recall that 1 cal=duncan takes a break from studying and goes to the gym to swim laps. if swimmi

quester [9]

For this problem, let's use the approach of dimensional analysis. This technique is done by cancelling out like units that appear both on the numerator and the denominator side. As a result, this technique will let you know that your final answer conforms to what parameter is asked. In this case, the final answer should be in kJ. We use the conversion: 1000 cal = 4.184 kJ The solution is as follows:

6.95×10⁵ cal * 4.184 kJ/1000 cal = 2,907.88 kJ

3 0

4 years ago

What is the spring coefficient of a spring that stores 4000 joules of energy

Verizon [17]

Answer:

222.2N/m

Explanation:

Given parameters:

Elastic potential energy = 4000J

Extension = 6m

Unknown:

Spring coefficient = ?

Solution:

The elastic potential energy is the energy stored within a string.

It is expressed as;

EPE = $\frac{1}{2}$ k e²

k is the spring constant

e is the extension

4000 = $\frac{1}{2}$ x k x 6²

8000 = 36k

k = 222.2N/m

6 0

3 years ago

Two men, Joel and Jerry, each pushes an object that are identical on a horizontal frictionless floor starting from rest. Joel an

Nataliya [291]

Answer:

The work done by Joel is greater than the work done by Jerry.

Explanation:

Let suppose that forces are parallel or antiparallel to the direction of motion. Given that Joel and Jerry exert constant forces on the object, the definition of work can be simplified as:

$W = F\cdot \Delta s$

Where:

$W$ - Work, measured in joules.

$F$ - Force exerted on the object, measured in newtons.

$\Delta s$ - Travelled distance by the object, measured in meters.

During the first 10 minutes, the net work exerted on the object is zero. That is:

$W_{net} = W_{Joel} - W_{Jerry}$

$W_{net} = F\cdot \Delta s - F\cdot \Delta s$

$W_{net} = (F-F)\cdot \Delta s$

$W_{net} = 0\cdot \Delta s$

$W_{net} = 0\,J$

In exchange, the net work in the next 5 minutes is the work done by Joel on the object:

$W_{net} = W_{Joel}$

$W_{net} = F\cdot \Delta s$

Hence, the work done by Joel is greater than the work done by Jerry.

7 0

4 years ago

A cylinder with rotational inertia I1=2.0kg·m2 rotates clockwise about a vertical axis through its center with angular speed ω1=

Mrac [35]

Answer:

a) 0.67 rad/sec in the clockwise direction.

b) 98.8% of the kinetic energy is lost.

Explanation:

Let us take clockwise angular speed as +ve

For first cylinder

rotational inertia $I$ = 2.0 kg-m^2

angular speed ω = +5.0 rad/s

For second cylinder

rotational inertia $I$ = 1.0 kg-m^2

angular speed = -8.0 rad/s

The rotational momentum of a rotating body is given as = $I$ ω

where $I$ is the rotational inertia

ω is the angular speed

The rotational momenta of the cylinders are:

for first cylinder = $I$ ω = 2.0 x 5.0 = 10 kg-m^2 rad/s

for second cylinder = $I$ ω = 1.0 x (-8.0) = -8 kg-m^2 rad/s

The total initial angular momentum of this system cylinders before they were coupled together = 10 + (-8) = 2 kg-m^2 rad/s

When they are coupled coupled together, their total rotational inertia $I_{t}$ = 1.0 + 2.0 = 3 kg-m^2

Their final angular rotational momentum after coupling = $I_{t}$ $w_{f}$

where $I_{t}$ is their total rotational inertia

$w_{f}$ = their final angular speed together

Final angular momentum = 3 x $w_{f}$ = 3 $w_{f}$

According to the conservation of angular momentum, the initial rotational momentum must be equal to the final rotational momentum

this means that

2 = 3 $w_{f}$

$w_{f}$ = final total angular speed of the coupled cylinders = 2/3 = 0.67 rad/s

From the first statement, the direction is clockwise

b) Rotational kinetic energy = $\frac{1}{2} Iw^{2}$

where $I$ is the rotational inertia

$w$ is the angular speed

The kinetic energy of the cylinders are:

for first cylinder = $\frac{1}{2} Iw^{2}$ = $\frac{1}{2}*2*5^{2}$ = 25 J

for second cylinder = $\frac{1}{2}*1*8^{2}$ = 32 J

Total initial energy of the system = 25 + 32 = 57 J

The final kinetic energy of the cylinders after coupling = $\frac{1}{2}I_{t}w^{2} _{f}$

where

where $I_{t}$ is the total rotational inertia of the cylinders

$w_{f}$ is final total angular speed of the coupled cylinders

Final kinetic energy = $\frac{1}{2}*3*0.67^{2}$ = 0.67 J

kinetic energy lost = 57 - 0.67 = 56.33 J

percentage = 56.33/57 x 100% = 98.8%

6 0

3 years ago

7. Convert 746 days to centuries.

timofeeve [1]

Answer: 0.0208 Centuries

Explanation:

There is 2.739*10^-5 centuries per 1 day.

We can take 746 days and multiply it by that 2.7 number to get how many centuries are in 746 days.

$746 *(2.793*10^{-5})$ = 0.0208 centuries

4 0

3 years ago