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Salsk061 [2.6K]
3 years ago
13

While watching a circus show, I counted out the number of acrobats and elephants. I counted 40 legs and 15 heads. How many acrob

ats did I see in the show?
Mathematics
1 answer:
Goryan [66]3 years ago
5 0

Answer:

y=10 ( number of acrobat)

Step-by-step explanation:

let x be the elephant and y the acrobat

elephant has 4 legs and acrobat 2

4x+2y=40

x+y=15  ⇒x=15-y

substitute for x in the equation:

4(15-y)+2y=40

60-4y+2y=40

-2y=40-60

y=-20/-2

y=10 ( number of acrobat)

number of elephant=15-10=5 elephants

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Answer:

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2. Second Option is correct , because by reflecting the shape I across  X axis and then by 90° counterclockwise rotation will take the Shape I in second quadrant ,where we are getting shape II.

3. a reflection of shape I across the y-axis followed by a 90° counterclockwise rotation about the origin takes the shape I in fourth Quadrant. →→ Incorrect option.

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6 0
3 years ago
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The correct option is B. Distributive property

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For more details follow the link:

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6 0
2 years ago
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Step-by-step explanation:

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