One as it intersects only on the Y axis
<span>For a parallelogram to be proven to be a rectange, the opposide sides must be parallel and the two adjacent sides must be perpendicular.
For two parallel sides, the slope of the two sides is equal.
Thus, for the parallelogram to be a rectangle, AB is parallel to CD.
The slope of AB = (y2 - y1)/(x2 - x1) while the slope of CD = (y4 - y3)/(x4 - x3)
Also, BC is perpedicular to CD.
For two perpendicular sides, the product of the slopes is -1.
The slope of BC is given by (y3 - y2)/(x3 - x2).
Therefore, for the parallelogram to be a rectangle.
(y2 - y1)/(x2 - x1) = (y4 - y3)/(x4 - x3) and (y4 - y3)/(x4 - x3) x (y3 - y2)/(x3 - x2) = -1.
The third option is the correct answer.</span>
Hi there! :)
Answer:
-8v + 3(v - 3) = 16
Distribute the 3:
-8v + 3(v) + 3(-3) = 16
-8v + 3v - 9 = 16
Combine like terms and simplify:
-5v - 9 = 16
-5v - 9 + 9 = 16 + 9
-5v = 25
Divide both sides by -5:
-5v/(-5) = 25/(-5)
v = -5.
The denominator can't be equal to 0.
The domain is all numbers except -3 and 3.
