Question

Determine the value of x and y

Answer 1

Step-by-step explanation:

IGH = JKL

GH = KL

12 = 36

12 × x = 36

x = 36 ÷ 12 = 3

IG =

$\sqrt{ {16 {}^{2} + 12}^{2} }$

= 20

y = 16 × 3 = 48

x =

$\sqrt{ {48}^{2} + {36}^{2} }$

= 60