An object is thrown in the air with an initial velocity of 10m/s from an initial height of 15m. The equation h(t)= -16t^2+32t+6
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Answer:
The values of k are 2/3 and -1
Step-by-step explanation:
Product of zeros = αβ= constant / coefficient of x^2 = 4/k
Sum of zeros =α+β = - coefficient of x / coefficient of x^2= -4/k
Given
Consider a= α and b= β
can be written as
if we add
in the above equation.
Putting values of αβ and α+β
The values of k are 2/3 and -1