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3 years ago

Kasabihan sa bibliya

1 answer:

3 0

Ang mga Kawikaan ay hindi lamang isang antolohiya kundi isang "koleksyon ng mga koleksyon" na may kaugnayan sa isang huwaran ng buhay na tumagal ng higit sa isang sanlibong taon. Ito ay isang halimbawa ng tradisyon ng karunungan sa Biblia, at nagtataas ng mga tanong ng mga halaga, moral na pag-uugali, kahulugan ng buhay ng tao, at tamang pag-uugali.

Umaasa ako na makakatulong ito!

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Convert to rectangular coordinates. use exact values. 7 sqrt 2, 135 degrees

Free_Kalibri [48]

Tan 135 = -1

so rectangular coordinates are (-7 sqrt2, 7 sqrt2)

7 0

3 years ago

Show me how to make 33 in four different ways

tamaranim1 [39]

30+3
11*3
10*3+3
60-30+3

(sorry if these didn't help i'm a beginner and i'm in 7th grade)

7 0

3 years ago

A population of bees is decreasing. The population in a particular region this year is 1,250. After 1 year, it is estimated tha

8_murik_8 [283]

To model this situation, we are going to use the decay formula: $A=Pe^{rt}$
where
$A$ is the final pupolation
$P$ is the initial population
$e$ is the Euler's constant
$r$ is the decay rate
$t$ is the time in years

A. We know for our problem that the initial population is 1,250, so $P=1250$ ; we also know that after a year the population is 1000, so $A=1000$ and $t=1$ . Lets replace those values in our formula to find $r$ :
$A=Pe^{rt}$
$1000=1250e^{r}$
$e^{r}= \frac{1000}{1250}$
$e^{r}= \frac{4}{5}$
$ln(e^{r})=ln( \frac{4}{5} )$
$r=ln( \frac{4}{5} )$
$r=-02231$

Now that we have $r$ , we can write a function to model this scenario:
$A(t)=1250e^{-0.2231t}$ .

B. Here we are going to use a graphing utility to graph the function we derived in the previous point. Please check the attached image.

C.
- The function is decreasing
- The function doe snot have a x-intercept
- The function has a y-intercept at (0,1250)
- Since the function is decaying, it will have a maximum at t=0:
$A(0)=1250e^{(-0.2231)(0)$
$A_{0}=1250e^{0}$
$A_{0}=1250$
- Over the interval [0,10], the function will have a minimum at t=10:
$A(10)=1250e^{(-0.2231)(10)$
$A_{10}=134.28$

D. To find the rate of change of the function over the interval [0,10], we are going to use the formula: $m= \frac{A(0)-A(10)}{10-0}$
where
$m$ is the rate of change
$A(10)$ is the function evaluated at 10
$A(0)$ is the function evaluated at 0
We know from previous calculations that $A(10)=134.28$ and $A(0)=1250$ , so lets replace those values in our formula to find $m$ :
$m= \frac{134.28-1250}{10-0}$
$m= \frac{-1115.72}{10}$
$m=-111.572$
We can conclude that the rate of change of the function over the interval [0,10] is -111.572.

7 0

2 years ago

David bought 3 dvds and 4 books for $40 at a yard sale. Anna bought 1 dvd and 6 books for $18. How much did each dvd and book co

Ber [7]

Answer:

A book is worth $1 and a DVD is worth $12.

Step-by-step explanation:

The equations (2 unknowns and two equations, d is for a DVD and b is for a book):

For David: 3d+4b=40

For Anna: d+6b=18

Now multiply the second equation with -3 and add to the first equation:

3d+4b=40

−3d−18b=−54

Combined equation: −14b=−14 and b=1 (means that each book is worth $1).

Now for DVD price, use the second equation:

d=18−6 or d=12 (means that each DVD is worth $12).

A book is worth $1 and a DVD is worth $12.

8 0

3 years ago

John is making baked goods for a party. He can either make muffins or bread, and he can use blueberries, bananas, apples, or cho

Margarita [4]

The total number of possible choices that John had for making baked goods for the party is 8.

<h3>What is Combination?</h3>

The combination helps us to know the number of ways an object can be arranged without a particular manner. A combination is denoted by 'C'.

$^nC_r = \dfrac{n!}{r!(n-r)!}$

where,

n is the number of choices available,

r is the choices to be made.

We know that the number of choices with John for his baked goods is only two which are muffins or bread, therefore, the choices of the baked good can be written as $^2C_1$ .

Also, the number of choices with John for flavors is four which are blueberries, bananas, apples, or chocolate chips, therefore, the choices of the flavor can be written as $^4C_1$ .

Now, the total possible choices that John had

= The choices of the baked good x The choices of the flavor

$=\ ^2C_1 \times ^4C_1\\\\=\ 8$

Hence, the total number of possible choices that John had for making baked goods for the party is 8.

Learn more about Combination:

brainly.com/question/11732255

8 0

2 years ago