Answer:
Density = 5751.66 gram per litre
Step-by-step explanation:
It is given that the density of a certain material 6 pounds per pint.
The conversion from pint to liter is as follows :
1 pint = 0.473 litre
The conversion from pounds to kg is as follows :
1 pound = 453.59 kg
We need to express the density from pounds per pint to grams per liter.
1 pound per pint = 958.611 gram per litre
So,
6 pound per pint = 958.611 × 6 gram per litre
6 pound per pint = 5751.66 gram per litre
14x - 129 (I think I’m so sorry if it’s wrong)
Answer:
Explanation:
1)<u> Principal quantum number, n = 2</u>
- n is the principal quantum number and indicates the main energy level.
<u>2) Second quantum number, ℓ</u>
- The second quantum number, ℓ, is named, Azimuthal quantum number.
The possible values of ℓ are from 0 to n - 1.
Hence, since n = 2, there are two possible values for ℓ: 0, and 1.
This gives you two shapes for the orbitals: 0 corresponds to "s" orbitals, and 1 corresponds to "p" orbitals.
<u>3) Third quantum number, mℓ</u>
- The third quantum number, mℓ, is named magnetic quantum number.
The possible values for mℓ are from - ℓ to + ℓ.
Hence, the poosible values for mℓ when n = 2 are:
- for ℓ = 1, mℓ = -1, 0, or +1.
<u>4) Fourth quantum number, ms.</u>
- This is the spin number and it can be either +1/2 or -1/2.
Therfore the full set of possible states (different quantum number for a given atom) for n = 2 is:
- (2, 0, 0 +1/2)
- (2, 0, 0, -1/2)
- (2, 1, - 1, + 1/2)
- (2, 1, -1, -1/2)
- (2, 1, 0, +1/2)
- (2, 1, 0, -1/2)
- (2, 1, 1, +1/2)
- (2, 1, 1, -1/2)
That is a total of <u>8 different possible states</u>, which is the answer for the question.
Answer:
Haha once again 1200 and 8.5 are the answers
Given is the function for number of adults who visit fair at day 'd' after its opening, a(d) = −0.3d² + 4d + 9.
Given is the function for number of children who visit fair at day 'd' after its opening, c(d) = −0.2d² + 5d + 11.
Any function f(d) to find excess of children more than adults can be written as follows :-
f(d) = c(d) - a(d).
⇒ f(d) = (−0.2d² + 5d + 11) - (−0.3d² + 4d + 9)
⇒ f(d) = -0.2d² + 0.3d² + 5d - 4d + 11 - 9
⇒ f(d) = 0.1d² + d + 2
